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The offspring of two parents that are heterozygous for a given trait have a percent chance of being homozygous for that trait?
Wiki User
∙ 12y ago
This would result in 1 heterozygous offspring. You can think of it like this: If the first parent is homozygous it would have AA alleles, the second heterozygous parent would be AB. When they mix genetically it would result in 4 combinations: AA, AA, AA, AB. As there is only one B there can only be one heterozygous offspring. This is not expected it is certain.
Wiki User
∙ 15y ago
Wiki User
∙ 12y agoThe offspring have a 25% chance to be homozygous dominant and a 25% chance to be homozygous recessive, so overall the chance is 50%.
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If a homozygous dominant is crossed with a homozygous recessive for a given trait the offspring will be?
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.
If a female fruit fly heterozygous for red eyes XRXr crossed with a white eyed male XrY what percent of their offspring would have white eyes?
Plato users, Heterozygous (Rr), red.
What percentage of the possible types of offspring had the same phenotype as the parents?
Hey there. To answer this accurately, i would need to know the genotypes of both parents. I'll show you a trick that works them out in a flash. A phenotype is the result of a genotype, which is the result of 2 alleles. Say if both parents were HOMOZYGOUS for brown hair, with their genotype would be BB, BB. Use a trick called a punnet square to answer this; _|B |B | B|BB|BB| <-- not the best punnet square, but the top row shows the first parents B|BB|BB| genotype (BB) and the side shows the second's. (BB) The cross of this shows all the children will have brown hair, as inherited from each parent. If the Mother had HOMOZYGOUS brown hair (BB), and the father had HETEROZYGOUS brown hair (Bb) the results would be 100% Brown hair too, because the brown hair gene (B) is dominant over the non brown hair gene (b). Below; _|B |B | B|BB|BB| <--- this shows the cross gives a 50% chance to be Homozygous for brown b|Bb|Bb| hair but 50% heterozygous for brown hair, but carrying a non- brown hair gene. If we cross 2 heterozygous parents, the results are shown: _|B |b | B|BB|Bb| b|bB|bb| <----- This shows the child has a 75% chance of having brown hair (either (BB or bB, Bb) and 25% of being non-brown (bb)). This can be used in any gene cross, but you must keep in mind that one gene will be dominant and one will be recessive. I used the brown hair gene as an example here, as I don't know whether it may be dominant or recessive to other hair colours. Also, if you were after a global statistic, I wouldn't know. I hope this helps you. Fletch
The first generation of offspring from the cross of two parents is called?
Durrrrr whats the trait??? Assuming this is what your really asking. Its PP X PP Then the result can only be PP if big P is dominant over little p. Form your questions better in the future! Apex: 100 percent heterozygous
How many genes out of a gene pair does a plant that is self pollinated get from each of its parents?
one from each parent out of a gene pair. Because each parents contributes fifty - fifty percent in the new offspring.
Which type of cross would produce 100 percent heterozygous offspring?
A cross between two homozygous parents will form a 100 percent chance of a heterozygous offspring. One homozygous parent must have the dominant allele, and the other must have the recessive allele. So, if the circumstances are correct, these characteristics will make for a 100 percent chance of a heterozygous offspring.
If a test cross between a homozygous recessive and heterozygous allele will yield what percent of offspring as homozygous recessive?
25%
A mother that is heterozygous for a trait and a father who is homozygous recessive for the same trait have offspring Use this information to complete the matching below Enter the letter of the item?
A. Offspring with heterozygous genotype 100 percent B. Offspring with homozygous dominant genotype 0 percent C. Offspring with at least one copy of recessive gene 50 percent
What is the result of a cross between an individual who is homozygous dominant and another who is homozygous recessive for a trait?
All the offspring will be heterozygous with a phenotype showing the dominant trait. Let the alleles be H (dominant) and h (recessive). All the gametes from the first individual will be H, and from the other, h. Thus all the offspring must be Hh.
What offspring is produced if a heterozygous n tall pea plant is crossed with a homozygousfor this trait what percent of the offspring will be heterozygous?
If a heterozygous tall pea plant, Aa, is crossed with a homozygous plant, AA, for the trait, you will have a one in one in four chance of the offspring being heterozygous. You will need to create a square and plug the traits in to see what the odds are.
What is an example of two heterozygous parents?
The possible genotypes of parents who are heterozygous would be found using a punnet square. The outcome would be 50 percent heterozygous dominant, 25 percent homozygous dominant, and 25 percent homozygous recessive.
What is the probability that an individual heterozygous for a cleft chin and individual homozygous for chin without cleft will produce offsprings that are homozygous recessive for chin without cleft?
The probability that an individual heterozygous for a cleft chin and an individual homozygous for a chin without a cleft will produce offspring that are homozygous recessive for a chin without a cleft is fifty percent. You can calculate this by making a Punnet square.
A parent that is homozygous for a dominant trait is crossed with a parent that is homozygous for the recessive trait What percentage of the offspring will display the dominant trait?
100% of the offspring will display the dominant trait because the homozygous dominant parent can only pass on the dominant allele. The offspring will inherit one dominant allele from the dominant parent and one recessive allele from the recessive parent, resulting in a heterozygous genotype expressing the dominant trait.
How can a pedigree be 100 percent accurate about what the genotypes of an offspring will be?
It cannot (unless the parents were homozygous), but it can help predict the odds of having a child with a genetic disorder.
What is the probaility that the offspring of a homozygous dominant individual and a homozygous recessive individual will exhibit the dominant phenotype?
100 percent.
If a homozygous dominant is crossed with a homozygous recessive for a given trait the offspring will be?
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.
What kind of offspring will a homozygous tall plant and a homozygous short plant have?
Presuming tall is a dominant allele (the 2nd parent is heterozygous and "tall" is it's phenotype), then the square would be as follows: Let T be the dominant gene for tall, and thus every genotype containing this (TT, or Tt) would produce a tall plant. Let t be recessive, and in the absence of T (tt) causes a plant to be small. So the homozygous tall parent would be TT, and the heterozygous tall parent would be Tt. So now you just have to cross them. During meiosis, every gamete from the TT genotype would contain a T allele. However, for the Tt genotype, there is equal chance each gamete will contain EITHER a T or a t. So the square would be: xxTxxT TxTTxTT txTtxTt As you can see, 2 out of the 4 offspring have a Tt genotype (heterozygous), so this translates to a 1/2 fraction, or 50%. Ignore the Xs in the table- if i just used spaces then all the letters crunched up on top of each other when i pressed save...it was the best i could do...:S
