1 millimolar = 0.001 M NaOH ( a base, remember )
- log(0.001 M NaOH)
= 3
14 - 3
= 11 pH
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pOH of 0.01 N NaOH is 2. We know pH + pOH = 14. So pH of a 0.01 N solution of NaOH will be 14 -2 = 12
pH of 1M NaOH is 14!
Should be 1.040.
pH of NaOH 0.1 M is 13
14
pH= 14.0
13
pH = 11
an acid is on the left side of the scale. that means the low nubers like 1,2,3. bases are on the right side or high numbers like12,13,14. did you knowthat 14 is the highest number it can go ( that I know of).
No is the answer. Sodium hydroxide is is such a strong alkali that it will 'burn' the cells just like acid does. So it is not found in body. Instead you have sodium bi carbonate. But you have very strong acid in stomach. Hydrochloric acid. Imagine acidity go on increasing ten times as you go from 6 to 5 and 5 to 4. And pH in stomach is 1 to 2. (Why does not stomach is 'not' charred at this pH ?) Pepsin works in high acidic pH only and almost stop working at 5.5 pH. So no question of digestion in sodium hydroxide, which is strong alkali with very high pH. If you lower the pH pepsin starts working again.
around 1-2 is the pH of stomach acid
Between the pH of 1-4.
Positive.
base
Supposed the acid and base are both strong: pH of the acid is 0.0 and the pH of the base (hydroxide) is 14.0
That depends on it concentration. 1 mole per liter NaOH (=40g/l) has a pH value of 14. 0.1 mole per liter has a pH of 13; 0.01 mole per liter gives pH=12, ...
THE PH VALUE ACIDIC SOLUTION VARIOUS FROM 0-6.9, WHILE THE BASIC SOLUTION VARIOUS FROM 7.1-1.4. THUS ,OUT OF HCL AND NaOH WILL HIGHER PH VALUE
- log(0.048 M NaOH) = 1.3 pH --------------need Molarity? 1/10 1.3 = 0.050 M H3O ---------------------
Strongest Acid is HCl. Then in order of acidic strength H2CO3 , NH3(solution) and finally NaOH. In words, Hydrochloric Acid ; pH = 1 Carbomic Acid ; pH ~ 5 Ammonia solutioon ; pH ~ 8 or 9 Sodium Hydroxide ; pH ~ 12
pKa= pH - log(A/HA) to clarify -log is subtract log E.g A buffer is prepared by adding .15 M of NaOH and .1 of a weak acid, HA. If the pH of the buffer is 8.15, what is the pKa of the acid? pH= 8.15 - log .15/.1 = 7.97
a pH=10 solution of NaOH should contain 0,0001 moles of NaOH/liter. (1 mole/liter for pH=14, 0,1 for pH=13, etc.) A mole of NaOH is 40g-s. (Na=23g O=16g H=1g) 0,0001 mole is 0,004gs. You need the amount necessary for a quarter of a liter, so you divide by four. The result is that you need 0,001gs of NaOH. So if you need to make that solution without any precise laboratory equipment, you should make much larger quantities and just measure 0,250 l-s.
The pH is the cologarithm of the activity of hydrogen ion in solutions; pH 14 is the pH of a strong base.
pH depends on concentration. Strong bases are for example: NaOH KOH Ca(OH)2 http://en.wikipedia.org/wiki/Base_(chemistry)
pH 1 to 2.Sulfuric acid is a strong diprotic acid: [H+] = 2* 0.15 = 0.30 mole/L H+pH = -log 0.30 = 0.52pH 2.
3.42 moles NaOH (39.998 grams/1 mole NaOH) = 137 grams NaOH