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1 millimolar = 0.001 M NaOH ( a base, remember )

- log(0.001 M NaOH)

= 3

14 - 3

= 11 pH

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13y ago
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15y ago

pOH of 0.01 N NaOH is 2. We know pH + pOH = 14. So pH of a 0.01 N solution of NaOH will be 14 -2 = 12

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16y ago

pH of 1M NaOH is 14!

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15y ago

Should be 1.040.

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11y ago

pH of NaOH 0.1 M is 13

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11y ago

14

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13y ago

pH= 14.0

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11y ago

13

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6y ago

pH = 11

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Q: What is the pH of a 1 millimolar NaOH soluiton?
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