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Pete throws a tennis ball horizontally from the top of the 50 m building Assume that the ball landed 100 m away from the buildingHow long did it take for the ball to reach the ground?
Wiki User
∙ 15y ago
it i simply a projectile motion
assuming the vertical component zero
apply the equation
y=(1/2) (g) (t2 )
y=height
g=9.8
if we did not assume the data is in suffcient to calculate the time
Wiki User
∙ 15y ago
Wiki User
∙ 15y agoThis uses simple dynamics and the kinematic equations.
Assumptions:
Neglect wind resistance
Gravity = 9.81m/s
Since the ball is launched from 50 meters and gravity constantly acts on the ball, the time of flight can be calculated from the equation d = vit + 1/2(at2). Since the initial velocity in the y direction is zero, the equation becomes d = 1/2(at2). Since d, 50m, and a, 9.81m/s, are known, t can be solved for. The answer I got is 3.19 seconds. Now, to solve for the velocity in the x direction, we will utilize this time.
Using the equation of d = v*t, the answer can be simply solved for using the 100m distance traveled and the 3.19 second flight time. The velocity is 31.3 m/s.
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