You'll make water, some heat and some bubbles. Not sure how practical that is. It might blow up in your face.
Research other standard acid/base neutralizations. If that's all you have on hand, apply for more funding.
And now, a poem:
Willie was a chemist;
Willie is no more.
What Willie thought was H2O
Was H2SO4.
(Golf swing.)
I think you just use C1V1 = C2V2 , but don't forget the stoichiometric ratio of1 NaOH 0.5 H2SO4NaOH:C1 = .1650 mol/LV1 = 26.48 mLH2SO4:C2 = ? (mol/L of H2SO4)V2 = 28.22 mL26.49 x .1650 (mmoles of OH-) = 2 * C2 x 28.22 (mmoles of H+ from H2SO4) =C2 = 0.5 * 0.1548848335 = 0.07744 (mol/L H2SO4)
Al2O3 + H2SO4 = Al2(SO4)3 + H2O
Ca(OH)2 + H2SO4 >> CaSO4 + 2H2O
H2so4
The balanced chemical equation would be K4FeC6N6 + KMnO4 + H2SO4 = KHSO4 + Fe2SO43 + MnSO4 + HNO3 + CO2 + H2O.
use a better site you dumby and get a life you Elmo
Salt plus Water. In this case the salt would be Sodium Sulphate.
NaCl doesn't react with KNO3.NaCl + AgNO3 = NaNO3 + AgCl(s)NaOH + HCl = NaCl + H2ONa2CO3 + 2 HCl = 2NaCl + CO2 + H2OBaCl2 + H2SO4 = BaSO4(s) + 2 HClCuSO4 and Zn(NO3)2 doesn't react.
I think you just use C1V1 = C2V2 , but don't forget the stoichiometric ratio of1 NaOH 0.5 H2SO4NaOH:C1 = .1650 mol/LV1 = 26.48 mLH2SO4:C2 = ? (mol/L of H2SO4)V2 = 28.22 mL26.49 x .1650 (mmoles of OH-) = 2 * C2 x 28.22 (mmoles of H+ from H2SO4) =C2 = 0.5 * 0.1548848335 = 0.07744 (mol/L H2SO4)
The general reaction for acid-base reactions is as follows: Acid + Base = Salt + Water In this case H2SO4 + 2 NaOH --> Na2SO4 + 2 H2O Actually: H2SO4 (aq) + NaOH (aq) ---> NaHSO4 (aq) + H2O(l) NaHSO4 (aq) + NaOH (aq) ---> Na2SO4 (aq) + H2O(l)
Sulfuric acid plus sodium hydroxide gives sodium sulfate plus water.
Fe2O3 + H2SO4
H2SO4+Hg
Pb + PbO2 + H2SO4 --> PbSO4 + H2O
Br2 + 2H2O + SO2 = H2SO4 + 2HBr
LiCl+H2SO4=LiHSO4+HCl
H2SO4 + ZnO => H2O + ZnSO4