10S + 40 HNO3 → 10 H2SO4 + 40 NO2 + H2O
S + 6HNO3 → H2SO4 + 6NO2 + 2H2O
S + 4HNO3 -→ SO2 + 4NO2 + 2H2O
1 nh3+ 2o2 >>>>> 1hno3 + 1h2o
I2 + 10 hno3 = 2 hio3 + 10 no2 + 4 h2o
The chemical reaction is:Na2CO3 + 2 HNO3 = 2 NaNO3 + CO2 + H2O
Combustion reaction
The reaction is:Pb(CO3)2 + 2 HNO3 = Pb(NO3)2 + 2 CO2 + H2O
The balanced equation for the reaction between HNO3 and NaHCO3 is: 2 HNO3 + NaHCO3 → NaNO3 + H2O + CO2
The missing chemicals are 2LiOH + 2LiNO3 = H2O + CO2 + 4LiNO3.
The chemical equation is:Sn + 4 HNO3 = SnO2 + 4 NO2 + 2 H2O
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
SO2 plus H2O equals H2SO3 which is Sulfurous Acid. CO2 plus H2O equals H2CO3which is Carbonic Acid. It also forms HNO3 which is nitric acid.
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
1 nh3+ 2o2 >>>>> 1hno3 + 1h2o
299 H2SO4 + 10 K4Fe(CN)6 + 122 KMnO4 = 60 CO2 + 5 Fe2(SO4)3 + 188 H2O + 60 HNO3 + 162 KHSO4 + 122MnSO4
The acid-base reaction between nitric acid (HNO3) and sodium hydroxide (NaOH) produces sodium nitrate (NaNO3) and water (H2O). The balanced chemical equation for this reaction is: HNO3 + NaOH → NaNO3 + H2O.
The reaction you provided is the dissociation of nitric acid (HNO3) in water. In this reaction, HNO3 donates a proton to water, forming hydronium ions (H3O+) and nitrate ions (NO3-), indicating that HNO3 is an acid.
The conjugate base for the equation HNO3 + NaOH -> H2O + NaNO3 is the nitrate ion (NO3-), which is formed when the strong acid HNO3 donates a proton to water (H2O) to form the weak conjugate base NO3-.
KOH + HNO3 --> KNO3 + H2O -------------------------------------site mis-correcting again. All letters capitalized.