10S + 40 HNO3 → 10 H2SO4 + 40 NO2 + H2O
S + 6HNO3 → H2SO4 + 6NO2 + 2H2O
S + 4HNO3 -→ SO2 + 4NO2 + 2H2O
1 nh3+ 2o2 >>>>> 1hno3 + 1h2o
I2 + 10 hno3 = 2 hio3 + 10 no2 + 4 h2o
The chemical reaction is:Na2CO3 + 2 HNO3 = 2 NaNO3 + CO2 + H2O
The reaction is:Pb(CO3)2 + 2 HNO3 = Pb(NO3)2 + 2 CO2 + H2O
Combustion reaction
The balanced equation for the reaction between HNO3 and NaHCO3 is: 2 HNO3 + NaHCO3 → NaNO3 + H2O + CO2
The missing chemicals are 2LiOH + 2LiNO3 = H2O + CO2 + 4LiNO3.
The chemical equation is:Sn + 4 HNO3 = SnO2 + 4 NO2 + 2 H2O
SO2 plus H2O equals H2SO3 which is Sulfurous Acid. CO2 plus H2O equals H2CO3which is Carbonic Acid. It also forms HNO3 which is nitric acid.
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
1 nh3+ 2o2 >>>>> 1hno3 + 1h2o
299 H2SO4 + 10 K4Fe(CN)6 + 122 KMnO4 = 60 CO2 + 5 Fe2(SO4)3 + 188 H2O + 60 HNO3 + 162 KHSO4 + 122MnSO4
The acid-base reaction between nitric acid (HNO3) and sodium hydroxide (NaOH) produces sodium nitrate (NaNO3) and water (H2O). The balanced chemical equation for this reaction is: HNO3 + NaOH → NaNO3 + H2O.
The reaction you provided is the dissociation of nitric acid (HNO3) in water. In this reaction, HNO3 donates a proton to water, forming hydronium ions (H3O+) and nitrate ions (NO3-), indicating that HNO3 is an acid.
The conjugate base for the equation HNO3 + NaOH -> H2O + NaNO3 is the nitrate ion (NO3-), which is formed when the strong acid HNO3 donates a proton to water (H2O) to form the weak conjugate base NO3-.
KOH + HNO3 --> KNO3 + H2O -------------------------------------site mis-correcting again. All letters capitalized.