IN this reaction the conjugate base is the nitrate ion, NO3-
The acid-base reaction between nitric acid (HNO3) and sodium hydroxide (NaOH) produces sodium nitrate (NaNO3) and water (H2O). The balanced chemical equation for this reaction is: HNO3 + NaOH → NaNO3 + H2O.
Nitrate = NO3-
This equation is NaHCO3 + HNO3 => NaNO3 + H2O + CO2 (g).
HNO3 (aq) + NaOH (aq) --> H2O (l) + NaNO3 (aq)
Nitric acid: HNO3 (acid) Sodium hydroxide: NaOH (base) This is therefore an acid-base reaction. Acid + Base --> Salt + Water Therefore: HNO3 + NaOH --> NaNO3 + H20 Or: Nitric acid + Sodium hydroxide --> Sodium Nitrate + Water
The acid-base reaction between nitric acid (HNO3) and sodium hydroxide (NaOH) produces sodium nitrate (NaNO3) and water (H2O). The balanced chemical equation for this reaction is: HNO3 + NaOH → NaNO3 + H2O.
Nitrate = NO3-
The balanced equation for the reaction between HNO3 and NaHCO3 is: 2 HNO3 + NaHCO3 → NaNO3 + H2O + CO2
This equation is NaHCO3 + HNO3 => NaNO3 + H2O + CO2 (g).
The balanced equation for Na + HNO3 is: 2Na + 2HNO3 -> 2NaNO3 + H2
HNO3 (aq) + NaOH (aq) --> H2O (l) + NaNO3 (aq)
Nitric acid: HNO3 (acid) Sodium hydroxide: NaOH (base) This is therefore an acid-base reaction. Acid + Base --> Salt + Water Therefore: HNO3 + NaOH --> NaNO3 + H20 Or: Nitric acid + Sodium hydroxide --> Sodium Nitrate + Water
HNO3+ NaOH = NaNO3+ H2O is a neutralization reaction
the balanced symbol equation for nitric acid and sodium hydroxideis as follows :potassium hydroxide + nitric acid → potassium nitrate + water.KOH + HNO3 → KNO3 + H2O
NaHCO3 + HNO3 = CO2 + H2O + NaNO3
Of course they react.H2S and NaNO3 is given out.
The chemical equation is:Sn + 4 HNO3 = SnO2 + 4 NO2 + 2 H2O