Nitrate = NO3-
The conjugate base for the equation HNO3 + NaOH -> H2O + NaNO3 is the nitrate ion (NO3-), which is formed when the strong acid HNO3 donates a proton to water (H2O) to form the weak conjugate base NO3-.
For the nitric acid (HNO3) the conjugate base is the ion (NO3)-.
Being the conjugate base of nitric acid (a strong acid), the nitrate ion is a weak base.
The conjugate acid of NaOH will be water. OH- has the ability to act as an acid or a base.
The conjugate base and conjugate acid for HS04 is: Conjugate acid is H2SO4 Conjugate base is SO42
The conjugate base for the equation HNO3 + NaOH -> H2O + NaNO3 is the nitrate ion (NO3-), which is formed when the strong acid HNO3 donates a proton to water (H2O) to form the weak conjugate base NO3-.
For the nitric acid (HNO3) the conjugate base is the ion (NO3)-.
Being the conjugate base of nitric acid (a strong acid), the nitrate ion is a weak base.
The conjugate acid of NaOH will be water. OH- has the ability to act as an acid or a base.
The conjugate base and conjugate acid for HS04 is: Conjugate acid is H2SO4 Conjugate base is SO42
The conjugate base of NH3 is NH2-, formed by removing a proton (H+) from NH3.
The conjugate base for CH3CH2COOH is CH3CH2COO-.
The conjugate base of HSO3- is SO32-.
The conjugate base of H2O is OH-. When H2O loses a proton, it forms the hydroxide ion OH-, which is the conjugate base of water.
The conjugate base of H3PO4 is H2PO4-. The formula for the conjugate base can be found by removing one proton (H+) from the acid molecule.
HNO3 is stronger than HNO2 because it has one more oxygen atom, making it a stronger acid. The presence of more oxygen atoms leads to greater electronegativity and more stability in the resulting conjugate base after donating a proton, resulting in increased acidity.
H2S and HS-