The C3H8O molecules will have a greater attraction in liquid rubbing alcohol than ch4 molecules in methane gas. This is due to the hydrogen bonding and dipole intermolecular forces that would occur between the polar alcohols. The nonpolar methane and methane gas will only experience London dispersion forces.
No, because rubbing alcohol molecules are polar and alcohol molecules can hydrogen bond with each other holding them together. That is why methane is a gas a room temperature and rubbing alcohols (all types of alcohols in fact) are liquids at room temperature
All the covalent bonds in CH4 are equal in polarity and are disposed in space so that a CH4 molecule has no net dipole moment. In contrast, a molecule of C3H8O contains one covalent bond, the O-H bond, which is more polar than any of the other covalent bonds in a C3H8O molecule and is not offset by the polarity of any other of these bonds, singly or in combination. Therefore, a C3H8O molecule does contain a net dipole moment. As a result, two C3H8O molecules can orient themselves in space so that the negative end of the dipole moment in one molecule is near the positive end of the dipole moment of the other molecule, causing an electrical attraction between the two molecules that can not have any counterpart in attractions between CH4 molecules.
C3H8O have a greater attraction for each other because they have stronger intermolecular forces (hydrogen-bonding) attraction molecules together. The easiest way to see this in action is that C3H8O is a liquid at room temperature and CH4 is a gas.
The C3H8O molecules will have a greater attraction in liquid
rubbing alcohol than ch4 molecules in methane gas. This is due to
the hydrogen bonding and dipole intermolecular forces that would
occur between the polar alcohols. The nonpolar methane and methane
gas will only experience London dispersion forces.
C3H8O molecules in liquid rubbing alcohol would have greater attraction for each other than CH4 molecules in methane gas?
C3H8.O .HERE O IS NASCENT. C2H5OH. reacts readily
The rubbing alcohol because methane is a gas and the bonds between gases are not very hard to break where as rubbing alcohol is a liquid and there a little harder to break
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methane + oxygen -> carbon dioxide + water 2 Methane molecules plus 4 Oxygen molecules gives 2 molecules of Carbon dioxide plus 4 Water molecules.
How many molecules are in 30 liters of methane (CH4) at STP
Yes, hydrogen diffuses faster than methane. The hydrogen molecule, H2, is the smallest of all molecules and it is considerably smaller than the methane molecule, CH4. Smaller molecules move faster, and therefore diffuse faster, at any given temperature, than larger molecules.
the answer is 8.45 molecules. Yay a 45th molecule. Weird huh.
1.79 Angstroms
methane + oxygen -> carbon dioxide + water 2 Methane molecules plus 4 Oxygen molecules gives 2 molecules of Carbon dioxide plus 4 Water molecules.
How many molecules are in 30 liters of methane (CH4) at STP
It represent a one molecule.CH4 stands for Methane
0.673 moles methane ( 6.022 X 10^23/1 mole CH4) = 4.05 X 10^23 molecules of methane
If the intermolecular forces are great enough they can hold the molecules together as a liquid. If they are even stronger they will hold the molecules together as a solid. Water has nearly the same mass as methane and ammonia molecules, but the greater molecular forces between water molecules causes the water to be liquid at room temperature, while ammonia and methane, with weaker intermolecular forces, are gases at room temperature.
Yes; the reaction is: CH4 + 2 O2 = CO2 + 2 H2O
If you think to 4 moles of methane the number is 24,088563428.10e+23.
The oxidation of inorganic molecules or methane.
8
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16
Actually methane molecules have no oxygen atoms. Methane is an organic compound ( a gas at room temperature) which is composed of only carbon and hydrogen atoms. Each methane molecule has 1 carbon atom bonded to 4 hydrogen atoms by covalent bonds.