The C3H8O molecules will have a greater attraction in liquid rubbing alcohol than ch4 molecules in methane gas. This is due to the hydrogen bonding and dipole intermolecular forces that would occur between the polar alcohols. The nonpolar methane and methane gas will only experience London dispersion forces.
There are approximately 4.68 x 10^22 molecules of methane in 0.123 moles of methane. This is calculated using Avogadro's number, which is 6.022 x 10^23 molecules per mole.
methane + oxygen -> carbon dioxide + water 2 Methane molecules plus 4 Oxygen molecules gives 2 molecules of Carbon dioxide plus 4 Water molecules.
Yes, hydrogen diffuses faster than methane. The hydrogen molecule, H2, is the smallest of all molecules and it is considerably smaller than the methane molecule, CH4. Smaller molecules move faster, and therefore diffuse faster, at any given temperature, than larger molecules.
No, methane is a covalent gas at room temperature and pressure. It is composed of individual molecules held together by covalent bonds.
When methane is burned, one molecule of methane (CH4) reacts with two molecules of oxygen (O2) to produce one molecule of carbon dioxide (CO2) and two molecules of water (H2O). So, for every molecule of methane burned, one molecule of carbon dioxide is produced.
There are approximately 4.68 x 10^22 molecules of methane in 0.123 moles of methane. This is calculated using Avogadro's number, which is 6.022 x 10^23 molecules per mole.
methane + oxygen -> carbon dioxide + water 2 Methane molecules plus 4 Oxygen molecules gives 2 molecules of Carbon dioxide plus 4 Water molecules.
It represent a one molecule.CH4 stands for Methane
Methane is soluble in oil because both substances are non-polar, meaning they have similar intermolecular forces. This allows methane molecules to mix well with oil molecules, resulting in solubility. Additionally, the small size of methane molecules enables them to fit between the larger oil molecules.
Yes; the reaction is: CH4 + 2 O2 = CO2 + 2 H2O
If you think to 4 moles of methane the number is 24,088563428.10e+23.
0.673 moles methane ( 6.022 X 10^23/1 mole CH4) = 4.05 X 10^23 molecules of methane
The oxidation of inorganic molecules or methane.
16.0 grams of methane (CH4) is equivalent to about 0.92 moles of methane, since the molar mass of methane is approximately 16.04 g/mol. In terms of molecules, this would be approximately 5.53 x 10^22 molecules of methane.
The high melting point of methane is due to its molecular structure. Methane molecules are held together by strong covalent bonds, making it difficult to break the bonds and transition from solid to liquid phase. Additionally, methane molecules are spherical and have a symmetrical shape, which contributes to the strong intermolecular forces between molecules.
To react completely with one molecule of methane (CH4), two molecules of oxygen (O2) are needed. This is because the balanced chemical equation for the combustion of methane is CH4 + 2O2 → CO2 + 2H2O. Each molecule of methane requires two molecules of oxygen to form carbon dioxide and water.
8