0.673 moles methane ( 6.022 X 10^23/1 mole CH4)
= 4.05 X 10^23 molecules of methane
16.0 grams of methane (CH4) is equivalent to about 0.92 moles of methane, since the molar mass of methane is approximately 16.04 g/mol. In terms of molecules, this would be approximately 5.53 x 10^22 molecules of methane.
To find the number of molecules in 30 liters of methane (CH₄), we can use the ideal gas law, which states that 1 mole of gas occupies 22.4 liters at standard temperature and pressure. Therefore, 30 liters of methane is approximately 1.34 moles (30 L / 22.4 L/mol). Since one mole contains about (6.022 \times 10^{23}) molecules (Avogadro's number), 1.34 moles of methane contains approximately (8.06 \times 10^{23}) molecules.
3.5 g CH4 x 1 mole/16 g x 6.02x10^23 molecules/mole x 4 H atoms/molecule = answer.
16 grams per mole. Methane is CH4. Look at the Periodic table: Carbon is 12 grams/mole and Hydrogen is 1 gram/mole, so 1*12 + 4*1 = 16.
One mole is equal to 6.022 x 1023 of anything. In this case, we are looking for molecules. So 1 mole=6.022 x 1023 molecules. We have 2.3 moles, so we want to know how many molecules are there. 2.3 mol CH4 x 6.022x1023 molecules CH4 / mol CH4 = 1.38x1024 molecules of CH4
Because they are.
Moles of methane. No half molecules, I think! 2.50 moles methane (1 mole C/1 mole CH4)(6.022 X 1023/1 mole C) = 1.51 X 1024 molecules of carbon --------------------------------------------
There are approximately 4.68 x 10^22 molecules of methane in 0.123 moles of methane. This is calculated using Avogadro's number, which is 6.022 x 10^23 molecules per mole.
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. So, in 30 liters of methane, there would be 30/22.4 = 1.3393 moles. One mole of methane contains 6.022 x 10^23 molecules, therefore 30 liters of methane at STP would contain 1.3393 * 6.022 x 10^23 = 8.07 x 10^23 molecules.
This is the number of Avogadro: 6,022 140 857(74).10e23.
16.0 grams of methane (CH4) is equivalent to about 0.92 moles of methane, since the molar mass of methane is approximately 16.04 g/mol. In terms of molecules, this would be approximately 5.53 x 10^22 molecules of methane.
Each molecule of methane contains one carbon atom, as shown by the formula for methane, CH4. Therefore, the number of carbon atoms in one mole of methane is the same as Avogadro's Number, about 6.022 X 1023.
To find the number of molecules in 30 liters of methane (CH₄), we can use the ideal gas law, which states that 1 mole of gas occupies 22.4 liters at standard temperature and pressure. Therefore, 30 liters of methane is approximately 1.34 moles (30 L / 22.4 L/mol). Since one mole contains about (6.022 \times 10^{23}) molecules (Avogadro's number), 1.34 moles of methane contains approximately (8.06 \times 10^{23}) molecules.
3.5 g CH4 x 1 mole/16 g x 6.02x10^23 molecules/mole x 4 H atoms/molecule = answer.
One centimeter cube of methane at STP will contain approximately (2.42 \times 10^{19}) molecules. This is because one mole of any gas at STP occupies 22.4 liters, so 1 cm^3 of methane is equal to (1/(22.4 \times 10^6)) moles, and a mole of methane contains 6.022 x 10^23 molecules.
False, They contain the same number of molecules, not the same number of atoms. H2O contains 3 atoms, so in 1 mole of water there are 6.022*10^23 * 3 = 1.81*10^24 atoms. CH4 contains 5 atoms, so in 1 mole of methane there are 6.022*10^23 * 5 =3.01*10^24 atoms.
3.01X10 24