Prove that capcitor will be open circuited if DC source is applied?
A capacitor will appear to be an open circuit to a DC source, but only after equilibrium is reached. Proof: A capacitor resists a change in voltage. The equation is ... dv/dt = i/c ... which means that the rate of change of voltage in volts per second is equal to current in amperes divided by capacitance in farads. A DC source has constant voltage. If you charge a capacitor to a constant voltage, then, at equilibrium, dv/dt is zero. This means that i must also be zero, since c is not zero. Ohm's law states that resistance is voltage divided by current. The limit of this is that, when current is zero, then resistance must be infinity. Therefore, the capacitor will have infinite resistance and appear to be open circuited.
That the 15th Amendment wasn't fair, that it applied to all women, that it was unconstitutional, and that it applied only to men.
the fifteenth amendment applied to woman as well
yes, air is also a source of electicity. For exampl, windmill.
action research is carried out to prove a scientific issue.
yes
How valid the source is and if it will help the researcher prove their thesis by adding it into the research they are presenting.
How valid the source is and if it will help the researcher prove their thesis by adding it into the research they are presenting.
How valid the source is and if it will help the researcher prove their thesis by adding it into the research they are presenting.
How valid the source is and if it will help the researcher prove their thesis by adding it into the research they are presenting.
the impedance of the capacitor is given by Xc=1/jwC where w=2*pi*f and for DC source f=0 hence Xc=infinity ie, the capacitor will provide infinite impedance for DC, or its Open circuit
state and prove sampling theory as applied to low pass signal