you have to determine what traits are used before you can do it and look at punnett square
It depends on the genotypes. But a punnett square shows all the possible outcomes of a genetic cross.
The girl must have a copy of the gene on each X chromosome. This means that she must have a father who is colorblind and a mother who is either a carrier or is colorblind.
Women can not be colorblind, only men. For questions like these a punnett square is useful. Men can not carry the colorblind trait, but women can. I know this is kind of confusing. When a carrier ( a woman with the color blind trait) has children with a man ( color blind or not) her kids will have 50% chance of having that trait. If its a girl, she will be the carrier. If its a boy, he will have the colorblind trait. SO TO ANSWER YOUR QUESTION: Theoreticaly, 1 of the daughters will be the carrier, and the son will have a 50% chance of being colorblind. Women can be colorblind, its just rare. About every 6400 women one is colour blind and with men, every 80 men 1 is colour blind.
there is a 50% chance that the child will be colorblind. If it is a boy, it will be colorblind, but if it is a girl, it will only be a carrier. Mother's chromosome is XrXr and Father's Chromosome is XRY, which means the children's genotypes will be XRXr if girl and XrY if a boy.
Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.
Yes. Because the colorblind trait is a sexlinked trait and is found in the X chromosome that is inherited from the mother, men that only have one X chromosome will develop colorblindness if the trait is found in this gene. For a woman to get it, she would need to have the colorblind gene on both x chromosomes. Therefore the girl´s dad would have to be colorblind and the mother at least a carrier.
A carrier is someone who does not have a disorder but carries the allele on to offspring.
In short, hemophilia has nothing to do with colorblindness, but YES, they could have a colorblind child if she is a carrier for the colorblindness gene. Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A woman will carry the colorblindness gene if: a. Her father is colorblind b. Any of her offpsring are colorblind She may carry the colorblindness gene if: a. Male family members (brothers, uncles, etc.) are colorblind A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy). So, If a woman has normal vision (assuming she does not have a family history of colorblindness), XX, and a man is colorblind, xY, they have several different chances for different offspring: Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) The short answer is that ALL CHILDREN WILL HAVE NORMAL VISION. However, all daughters will be CARRIERS, meaning they can pass colorblindness on to their children.
Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy). So, If a woman is a carrier, Xx, and a man is normal, XY, they have several different chances for different offspring: XX (a normal girl) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) xY (a colorblind boy) The short answer is, that if a woman has a boy, he has a 50% chance of being colorblind.
Each parent must have the recessive allele for colorblindness.
girl
The daughter's father would have to have been colour blind, and the mother would need the inheritive gene from her father (the mother doesn't nessecarily need to show it, just have a colourblind father) in order for a female to end up actually colourblind. However, it's extremely rare.
I know that a child can only become colorblind when both parents are colorblind. =============================================== There are number of types of color deficiencies (the correct name). These people are not really color 'blind'. I'll describe the common one. The most common type is the x-linked recessive congenital red/green deficiency. That means the defective gene is on the x-chromosome. So, a mom can be a carrier and still with normal vision since she has two x chromosomes. Since the father has only one x chromosome, he would be color deficient if he has the defective gene. What the above also means is that the affected father cannot give this to his sons, but all his daughters would be carriers. A carrier mom with a normal father would have 50:50 of the sons with the defective gene and 50:50 of daughters would be carriers. When a carrier woman and the affected man have kids, 50% of girl will be carrier and 50% of girl will be color deficient. Half the boys will be normal and half would have the condition. Notice that this is the reason you don't see many woman with this condition.