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The daughter's father would have to have been colour blind, and the mother would need the inheritive gene from her father (the mother doesn't nessecarily need to show it, just have a colourblind father) in order for a female to end up actually colourblind. However, it's extremely rare.

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What if Mary and her mother are both colorblind is Mary's father colorblind too?

If Mary's mother is colorblind, and therefore carries the colorblind gene on one of her X chromosomes, then Mary would inherit that gene as well. If Mary's father is colorblind, he would have to pass on his X chromosome with the colorblind gene to Mary, making her colorblind too. If only Mary's mother is colorblind, Mary's father is likely not colorblind.


What genotypes would the parents need to have in order to potentially have a child with cystic fibrosis?

In order to potentially have a child with cystic fibrosis, both parents would need to be carriers of the recessive gene for the condition. This means that both parents would need to have the genotype "Aa" for the child to have a chance of inheriting the condition.


For each phenotype give the genotypes that are possoble for Patrick?

Without knowing the specific phenotypes in question, it is difficult to provide exact genotypes for Patrick. However, genotypes result from the combination of alleles a person inherits from their parents. For example, if a phenotype is related to eye color, genotypes could include combinations of alleles for brown, blue, or green eye color. Patrick's genotypes would depend on the specific alleles he inherits for the given phenotype.


In humans normal color vision is dominant over colorblindness. A colorblind male marries a female who is a carrier for color blindness. What is the probability that a colorblind child would be born to?

The probability of a colorblind child being born is 50%. This is because the male passes his Y chromosome to all his sons, and since he is colorblind, his sons will inherit the colorblind gene from him. The daughters will inherit their X chromosome from the mother and have a 50% chance of being carriers like her.


How do you set this up Two heterodox red flowers (white flowers are recessive) are crossed.?

When crossing two heterozygous red flowers (Rr), you would use a Punnett square to determine the possible genotypes and phenotypes of the offspring. In this case, the genotypes of the parents are Rr x Rr. The possible offspring genotypes would be RR, Rr, and rr, with a phenotypic ratio of 1 red : 2 pink : 1 white flower.

Related Questions

A womens father is colorblind She marries a colorblind man Will there son or daughter be colorblind?

Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.


What would the genotypes of parents have to be to have a color blind daughter?

The daughter's father would have to have been colour blind, and the mother would need the inheritive gene from her father (the mother doesn't nessecarily need to show it, just have a colourblind father) in order for a female to end up actually colourblind. However, it's extremely rare.


What is the result from a cross between the parents Ww and Ww?

The genotypes produced from a cross between Ww and Ww would be: WW Ww Ww ww -The cross between these two genotypes would produce gametes with genotypes in a 1:2:1 ratio.


What if Mary and her mother are both colorblind is Mary's father colorblind too?

If Mary's mother is colorblind, and therefore carries the colorblind gene on one of her X chromosomes, then Mary would inherit that gene as well. If Mary's father is colorblind, he would have to pass on his X chromosome with the colorblind gene to Mary, making her colorblind too. If only Mary's mother is colorblind, Mary's father is likely not colorblind.


In cocker spaniels black coat color is dominat to red Two black cockers have eight puppies 5 black and 3 red What are the genotypes of the parents?

The parents genotypes will be Black and Red. BLACK being the dominant and red the recessive. The puppies genotypes would be Black and red, Black and Black, red and red.


Is a carrier for colorblindness is colorblind?

Not necessarily. The allele for colorblindness is recessive. For a female, in order to be colorblind she must have to recessive alleles for colorblindness. Example: XcXc would be colorblind. XCXc would be a carrier for colorblindness, but not colorblind. For a male, because colorblindness is a sex-linked gene, he only needs one allele to be colorblind. Example: XcY is colorblind. XCY is not colorblind.


how would you write the genotypes for the parents?

well i only put this so i can get points but please be more specific about your question


Are donkeys colorblind?

Nobody really knows, people say cats are colorblind when they are not really. So I would say "No." donkeys are not colorblind


What would your daughter in laws parents be called?

I don't know what they are called in English, but in Hindi, your daughter in law's parents would be called "Samdhees".


Can an A plus and an A- parents have an O- child?

Yes. It would take too long to explain genotypes and phenotypes, just know that it is possible.


How could two parents with blood types a and b have a child with o?

If the parents had the genotypes AO and BO, then they could have a child with Type O blood (there would be a 25% chance of this occurring).


What genotypes would the parents need to have in order to potentially have a child with cystic fibrosis?

In order to potentially have a child with cystic fibrosis, both parents would need to be carriers of the recessive gene for the condition. This means that both parents would need to have the genotype "Aa" for the child to have a chance of inheriting the condition.