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this means that the parents are rryy and RRYY (R-rough, r-smooth, Y-yellow, y-white skin)

the F1 population would all be rough hair and cream coloured skin - phenotype while the genotype would be RrYy. since Rr is dominant therefore rough and since Yy is codominant therefore cream coloured skin

now if u self them u get 4 different types of gametes: RY, Ry, rY, ry

now putting them in a mendalian double hybrid cross u get the genotypes

RRYY-1- rough hair yellow skin

RRYy- 2 - rough hair cream skin

RrYY-2 - rough hair yellow skin

RrYy-4 - rough hair cream skin

RRyy-1 - rough hair white skin

Rryy-2 - rough hair white skin

rrYY-1 - smooth hair yellow skin

rrYy-2 - smooth hair cream skin

rryy-1 - smooth hair and white skin

there fore your phenotypic ratios would be

rough hair and yellow skin - 3

rough hair and cream skin - 6

rough hair and white skin - 3

smooth hair and yellow skin - 1

smooth hair and cream skin - 2

smooth hair and white skin - 1

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Q: Pure-breeding yellow guinea pigs crossed with pure-breeding white ones produce only cream-colored offspring This pattern indicates incomplete dominance Rough hair is found to be dominant to smooth h?
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