No they are not the products.Product is as this. H2SO3
SO2 plus H2O equals H2SO3 which is Sulfurous Acid. CO2 plus H2O equals H2CO3which is Carbonic Acid. It also forms HNO3 which is nitric acid.
To balance the equation SO2 + H2S = S + H2O, we need to ensure that there are equal numbers of each type of atom on both sides of the equation. Begin by placing coefficients in front of the compounds to balance the number of sulfur and hydrogen atoms, then balance the oxygen atoms last by adjusting the coefficient for H2O. The balanced equation is SO2 + 2 H2S = 3 S + 2 H2O.
The chemical reaction is:SO2 + 2 H2 = 2 H2O + S
There are different possible answers here; in fact several of them. The two most obvious ones are: S + O2 --> SO2 : SO2 + H2O --> H2SO3 and: 2 S + 3 O2 --> 2 SO3 : 2 SO3 + 2 H2O --> 2 H2SO4 That just shows the balance; it does not point out whether the reaction requires several steps or special catalysts etc. For example, the second reaction might need a catalyst like platinum or vanadium pentoxide, or it could take a different course like: 2S +2O2 --> 2SO2 : 2SO2 + 2H2O --> 2H2SO3 : 2 H2SO3 + O2 --> 2 H2SO4
Yes, under suitable conditions per Patent 3,226,222 "High nitrogen reaction products of nh3-p2o5 and process therefor" (see United States Patent US3226222 link below) one can, in suitable conditions, form NO2 which reacts with excess ammonia, water and air to form NH4NO3. The creation of some Urea is almost mentioned.
SO2 plus H2O equals H2SO3 which is Sulfurous Acid. CO2 plus H2O equals H2CO3which is Carbonic Acid. It also forms HNO3 which is nitric acid.
To balance the equation SO2 + H2S = S + H2O, we need to ensure that there are equal numbers of each type of atom on both sides of the equation. Begin by placing coefficients in front of the compounds to balance the number of sulfur and hydrogen atoms, then balance the oxygen atoms last by adjusting the coefficient for H2O. The balanced equation is SO2 + 2 H2S = 3 S + 2 H2O.
10S + 40 HNO3 → 10 H2SO4 + 40 NO2 + H2OS + 6HNO3 → H2SO4 + 6NO2 + 2H2OS + 4HNO3 -→ SO2 + 4NO2 + 2H2O
The chemical reaction is:SO2 + 2 H2 = 2 H2O + S
Here are two chemical reactions:2 SO2 + CH4 = S2 + 2 H2O + CO2SO2 + 2 H2S = 3 S + 2 H2O
This is a Bronsted question. Hs- is the acid in this which makes H2O a base. Therefore S-2 is the conjugate base and the H3O+ hydronium ion is the conjugate acid.
There are different possible answers here; in fact several of them. The two most obvious ones are: S + O2 --> SO2 : SO2 + H2O --> H2SO3 and: 2 S + 3 O2 --> 2 SO3 : 2 SO3 + 2 H2O --> 2 H2SO4 That just shows the balance; it does not point out whether the reaction requires several steps or special catalysts etc. For example, the second reaction might need a catalyst like platinum or vanadium pentoxide, or it could take a different course like: 2S +2O2 --> 2SO2 : 2SO2 + 2H2O --> 2H2SO3 : 2 H2SO3 + O2 --> 2 H2SO4
Sulphur plus Oxygen gives Sulphur dioxide.... S + O2 = SO2
CuCO3(s) + H2SO4(aq) → CuSO4(aq) + CO2(g) + H2O(l)
Dilute Hydrobromic acid react with Sodium Thiosulfate to produce Sodium Bromide, Sulfur Dioxide, Sulfur and Water, according to the following equationNa2S2O3 +2 HBr ----> 2 NaBr + S + SO2+ H2O
Yes, under suitable conditions per Patent 3,226,222 "High nitrogen reaction products of nh3-p2o5 and process therefor" (see United States Patent US3226222 link below) one can, in suitable conditions, form NO2 which reacts with excess ammonia, water and air to form NH4NO3. The creation of some Urea is almost mentioned.
The reaction between hydrogen sulfide (H2S) and sulfur dioxide (SO2) is a redox reaction that forms sulfur (S) and water (H2O) as products. This reaction can be represented as: 2H2S + 3SO2 → 2S + 3H2O