int main(const int argc, const char** argv) {
// print the first 10 Fibonacci numbers recursively
fib_rec(10);
// print the first 10 Fibonacci numbers iteratively
fib_it(10);
return 0;
}
// simple starting interface for recursive algorithm
void fib_rec(const unsigned int max) {
}
// recursive part of algorithm
}
}
// iterative solution
void fib_it(const unsigned int max) {
}
}
Exactly what do you mean by 'C program in Java'
You mean you have written a program, but you don't understand it? Well, how could I explain it without seeing it?
i dn't know. haha
//to generate Fibonacci series upto a range of 200....(in C).... #include<stdio.h> main() { int a,b,c,i; a=0; b=1; printf("\n FIBONACCI SERIES .....\t"); i=1; while(i<=(200-2)) { c=a+b; printf("\t%d",c); a=b; b=c; i++; } }
Yes, this can be done. For example for Fibonacci series. You will find plenty of examples if you google for the types of series you need to be generated.
#include #include void main() { clrscr() int a=0,b=1,c,i,n; coutn cout
To write a C program that calculates the Fibonacci series up to a given number, you can use a loop to generate the series. Start by initializing the first two Fibonacci numbers (0 and 1) and then repeatedly compute the next number by adding the two preceding numbers until you reach or exceed the specified limit. Here’s a simple example: #include <stdio.h> int main() { int n, t1 = 0, t2 = 1, nextTerm; printf("Enter a positive integer: "); scanf("%d", &n); printf("Fibonacci Series: %d, %d", t1, t2); for (int i = 3; i <= n; ++i) { nextTerm = t1 + t2; printf(", %d", nextTerm); t1 = t2; t2 = nextTerm; } return 0; } This program prompts the user for a number and prints the Fibonacci series up to that number.
/*WAP to display Fibonacci series*/ #include<stdio.h> #include<conio.h> void main() { int i,a=0,b=1,c; scanf("%d",&n); printf("%d\n%d",a,b); for(i=0;i<n;i++) { c=a+b; a=b; b=c; printf("\n%d",c); } getch(); }
[ Fibonacci series___: ] #include<stdio.h> int main(void) { int n,i,c,a=0,b=1; printf("Enter Fibonacci series of nth term : "); scanf("%d",&n); printf("%d %d ",a,b); for(i=0;i<=(n-3);i++) { c=a+b; a=b; b=c; printf("%d ",c); } }
to print the Fibonacci series until 100 you can take the input in d to make it run for whatever value you want void main(){ int a,b,c,d; a=0; b=1; c=1; d=100; while(c<d) { printf("%d\n",c); c=a+b; a=b; b=c; } }
see the program
#include<stdio.h> #include<conio.h> void main() { printf("The first 20numbers of Fibonacci series are:"); int a=0, b=1, c, n=2; printf("%d \t, %d", &a, &b); while(n<20) { c=a+b; printf("\t %d", &c); a=b; b=c; n++; } getch(); }