at 1 khz is .6volts
Adding a DC source to a square wave signal will alter the base line of the wave without changing the peak-to-peak value. For example, if a square wave has a +4V baseline and a +2VDC source is introduced, the resulting square wave will have a +6V baseline. This of course will also affect the high and low peaks of the signal. Assuming that our example has a high peak of +9V and a low peak of -1V (with a total of 10V peak-to-peak), the added +2VDC source would result in a high peak of +11V and a low peak of +1V; however, the total peak-to-peak value remains unchanged at 10V peak-to-peak.
A: while a step can be of both polarity but it is a level change and it is DC LEVELS
This DC voltage is called the DC offset. Any decent signal generator will be able to add DC offset to the signal it generates. If you don't have one, simply connect a DC voltage to your signal.
It is called ( pulsed DC ).
ac
Actually ,Vrms is the root mean square voltage for example, consider voltages 5V,10V,2V So Vrms is the root value of {[(5*5)+(10*10)+(2*2)]/3} And Vpeak is 10V Thanks!!!!!(Zayed)
use kvl or kcl
The Amplification is much high during acmode because of transister conducts boththe Half cycles.But in DC the transister conducts only in positive half cycles.So the Amplification of AC signal greater than DC signal.
delta f over delta dc-v
The operation of a rectifier is to conver a AC signal to a pulsating DC signal
chopper use a ststeing perpose..... dc means direct current that is low voltage
using a rectifier, which converts the AC signal into a pulsating DC signal, and then using a filter to smooth out the pulsations in the signal, resulting in a steady DC output.