The 8086/8088 has an internal 20-bit address bus and 16-bit data bus. Externally, the address bus is 20-bits, and the data bus is 16-bits for the 8086 and 8-bits for the 8088.
The data bus in the 8086 is 16 bits in size, while the address bus is 20.
The 8086/8088 has a 20 bit address bus.
The address bus in the 8085 is 16 bits wide.
The data bus in the 8086 is 16 bits in size, while the address bus is 20 (16bits would only address 64KB of memory, an extra 4 bits allows to address the total of 1MB, this is done trough segmentation of the memory). To form a multiplexed of data bus and address bus, four bits of 8086 address bus are grounded.
It depends on the size of the address bus, which is often different than the size of the data bus.If the address bus were 8 bits, then you could address 256 locations.If the address bus were 16 bits, such as in the 8085, then you could address 65,536 locations.If the address bus were 20 bits, such as in the 8086/8088, then you can address 1,048,576 locations.
It is my understanding that the 80286 has a 16-bit data bus. This was a doubling of the original 8086/8088 processors.
You cannot address 1GB memory with the 8085 or the 8086/8088 without some kind of external demultiplexor that is software controlled. The address bus on the 8085 is 16 bits, giving addressibility of 64KB; while the address bus on the 8086/8088 is 20 bits, giving addressibility of 1MB. To address 1GB, you need a 30 bit address bus.
for demultiplexing address/data bus
220 or 1,048,576 locations, otherwise known as 1 meg. If its an 8 bit bus, we are talking about 1 megabyte. That happens to be the size of the address bus of the original 8086/8088 microprocessor.
128Kb
The difference between the 8086 and the 8088 is that the 8086 has a 16 bit data bus and that the 8088 has an 8 bit data bus. Both processors are the same 16 bit processor, and both have a 20 bit address bus. The 8086 is twice as fast as the 8088 in terms of data transfer rate on the bus for the same bus clock speed.
The 8086 has 16 data bus lines and 20 address bus lines because that is how Intel designed it. They wanted a processor that was more powerful than the 8085, which has an 8 bit data bus and a 16 bit data bus, so they increased both bus sizes accordingly.
The Instruction Pointer (IP) in an 8086 microprocessor contains the address of the next instruction to be executed. The processor uses IP to request memory data from the Bus Interface Unit, and then increments it by the size of the instruction.
8086 has 20 address lines. Therefore it can address 220 bits or 1,048,576 bits of memory, or roughly 1 MB (mega byte).