Sodium will lose 1 electron in its compounds.
The nonmetals usually gain or share however many electrons they need to complete their outer shell. Metals tend to lose the electrons in their outer shell, so that one of the inner shells essentially becomes the outer shell.
It will lose 2 electrons.
No. Electrons gain energy as they move up the chain, i.e. in more outer shells.
The octet rule states that atoms tend to gain, lose, or share electrons in order to have a full outer shell of 8 electrons, like the noble gases. Representative elements either gain or lose electrons to achieve this stable electron configuration, becoming ions with a charge that corresponds to the number of electrons gained or lost.
Oxygen tends to gain two electrons to fill its outer shell, resulting in a deficiency of electrons.
Sodium has one outer ring electron, and chlorine has seven outer ring electrons. Sodium tends to lose its outer electron, while chlorine tends to gain an extra electron to achieve a stable electron configuration.
Bromine has 7 electrons in its outer shell and needs to gain one electron to have a full outer shell and become an ion. It will gain this electron from an atom that has one electron in its outer shell such as Lithium or Sodium.
Sodium has 1 valence electron in its outer shell. By losing this electron, sodium achieves a full outer shell, which is more stable. This stable configuration is achieved by following the octet rule, where atoms tend to gain, lose, or share electrons to have 8 electrons in their outer shell.
Two electrons are needed to fill the outer shell of a sodium atom. The outer shell for sodium is the 3s sublevel. A neutral sodium atom has one electron in its 3s sublevel. Since atoms undergo chemical bonding in order to gain a noble gas electron configuration, called an octet, sodium atoms will lose their single 3s electron, becoming sodium atoms with a 1+ charge. By doing this, sodium ions become isoelectric with the noble gas neon, and achieve an octet, becoming stable.
An element that has two outer electrons is carbon. Carbon would not use the energy to gain six more electrons when it can easily get rid of the two outer electrons.
Each sodium atom will lose one electron to achieve a complete octet in its outer shell, as the octet rule dictates atoms will gain or lose electrons to achieve a stable electron configuration with 8 electrons in the outer shell.
Because atoms like to have a full outer shell - a sodium (1+) ion previously had 1 electron in it's outer shell, but it loses a (negatively charged) electron to gain a +1 charge. Chlorine, however, usually has 7 electrons in it's outer shell, but it gains a (negatively charged) electron to gain a -1 charge. Remember; gaining electrons = negative ions losing electrons=positive ions
Arsenic, with an atomic number of 33, will gain 3 electrons to have a filled outer shell, achieving stability with 8 electrons in its outer shell like a noble gas.
Sodium typically loses one electron to achieve a stable electron configuration, forming a +1 ion. This is because sodium has one electron in its outermost shell, and losing it allows sodium to achieve a full outer shell, similar to the noble gas configuration.
The transfer of an electron between a sodium atom and a chlorine atom occurs because sodium has one electron in its outer shell that it wants to lose to achieve a more stable electron configuration, while chlorine has seven electrons in its outer shell and can gain one from sodium to complete its outer shell and achieve stability by forming a full octet. This transfer of electrons results in the formation of sodium chloride, an ionic compound.
Sodium has one electron in its outer shell, which it wants to lose, while chlorine has seven electrons in its outer shell, which it wants to gain. When they come together, sodium loses an electron to chlorine, forming a stable ionic bond between sodium cation and chlorine anion, resulting in the formation of sodium chloride (table salt).
Sodium (Na) tends to lose electrons to achieve a full outer electron shell, which allows it to reach a stable electron configuration. This results in Na forming a +1 cation.