CH3CH2NH2 + H2O -> CH3CH2OH + NH3
Structure tends to correlate with the equation, so one would think that the central hub would be the Carbon, and everything would branch off from there
H3bo3 + 3ch3oh = b(och3)3 + 3h2o
not sure
To find the number of moles, divide the given mass of H3BO3 by its molar mass. The molar mass of H3BO3 is calculated as (31.01) + (111) + (3*16) = 61.83 g. Therefore, 61.83 g H3BO3 is equal to 1 mole of H3BO3.
Ka= [H+] [H2BO3-] / [h3BO3] (Apex)
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
CH3OH, also known as methanol, is a polar molecule because it contains a polar covalent bond between carbon and oxygen due to the difference in electronegativity between the two atoms. This creates a partial positive charge on the carbon atom and a partial negative charge on the oxygen atom, leading to an overall dipole moment in the molecule.
not sure
Ka= [H+] [H2BO3-] / [h3BO3] (Apex)
Methane, CH4 Methanol, CH3OH Methanal, CH2O Methyl chloride, CH3Cl
Yes, boric acid (H3BO3) can react with vinegar (acetic acid) to form a boric acid ester. This reaction can create a compound called "boric acid ester of acetic acid," which is generally used as a cleaning agent or insecticide.
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
CH3OH is molecular.
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
ammoniagasboricacidammonium-borate complexexcessboric acidNH3 +H3BO3→NH4 + H2BO-3 +H3BO3
H3bo3
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Boric Acid