Substance weighing 124g heated in boiling water to 100 deg C placed in a calorimeter w300.0g of water temp of water increased from 20C to26C Heat of substance transferred to water?

Answer 1

Okay looney, number one, stop cheating on your chemistry test. Number two, try using proper grammar in the future. It allows you to be less confusing and get a better answer.

Since the heat capacity of one gram of water is 4.2 Joulle per gram, we can take 6 (26C - 20C = heat raised = 6) and multiply that by 4.2 J (the amount of energy put into each gram of water) and 300.0 (how many grams there are)

so: 4.2 J x 6*C x 300.0 g let's whip out the calculator

= 7560 J*Cg

We're not done yet. We need to compensate for how many grams are in the substance, and how much the temperature has decreased. Since we know that 100*C is our constant, and that the substance has decreased to 26*C (assumably) we need to figure out how many degrees we lost in total.

100*C - 26*C = 74*C 74*C x 124 g = 9176 *Cg

Now we divide the two so we can get an answer in Joules.

7560 J*Cg / 9176 *Cg = 0.833 J because everything else eliminates.

Try that one and see what you get.