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For the last 1.5m:
s = ut + (1/2)at2
1.5 = ut + (1/2)*10*(109)2
1.5 - (1/2)*10*(109)2 = u * 109
u = -545 ms-1

It seems that for this situation to even exist, the lead weight must start going upwards from 1.5m at a speed greater than the speed of sound. This cannot happen if it's dropped off a building, obviously.

For the situation to be believable, the time would have to be much shorter, or the distance much larger.

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Q: THow high is the building if the time it takes for a lead weight dropped from the top of the building to fall the last 1.5 m before hitting the ground is 109s?
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