12.90
(Explanation): use charle's law for this one. V/T=V/T. we know the temperatures in both scenarios, and we're trying to solve for the volume in the beginning. Remember temperature in Kelvin! So, plug in what we know to get V/224.97K =29.164/508.59K. Now, cross-mulitply to solve for V. Equation now looks like this 508.59V=6561.02508. Now, divide by 508.59 on both sides to get 12.90042093. Round to 4 sig figs, 12.90 DONE!
- by the variation of the temperature- by the variation of the pressure
The volume of one mole of gas at a standard temperature and pressure is 22.4 liters. Multiply 22.4 liters by 0.25 moles to get a volume of 5.6 liters.
An experimental gas law is the Charles Law. The formula used is original volume/original temperature= new volume/new temperature. The law describes expansion of gases with heat.
It would be approx 9042 litres.
3.5 litre if pressure is kept constant.
Assuming pressure is constant, like you said, volume and temperature have a direct relationship. As temperature increases, volume increases; as temperature decreases, volume decreases. Setting up a algebraic direct proportion, you get approximately 3.84 liters for the balloon at 285 degrees K.
This problem can be solved with the ideal gas law. The original pressure and volume of the container are proportional the final pressure and volume of the container. The original pressure was 1 atmosphere and the original volume was 1 liter. If the final volume is 1.8 liters, then the final pressure is 0.55 atmospheres.
Of course. But at STP, any gas has a standard volume of 22.4 Liters.
BOYLES LAW The relationship between volume and pressure. Remember that the law assumes the temperature to be constant. or V1 = original volume V2 = new volume P1 = original pressure P2 = new pressure CHARLES LAW The relationship between temperature and volume. Remember that the law assumes that the pressure remains constant. V1 = original volume T1 = original absolute temperature V2 = new volume T2 = new absolute temperature P1 = Initial Pressure V1= Initial Volume T1= Initial Temperature P2= Final Pressure V2= Final Volume T2= Final Temperature IDEAL GAS LAW P1 = Initial Pressure V1= Initial Volume T1= Initial Temperature P2= Final Pressure V2= Final Volume T2= Final Temperature Answer BOYLES LAW The relationship between volume and pressure. Remember that the law assumes the temperature to be constant. or V1 = original volume V2 = new volume P1 = original pressure P2 = new pressure CHARLES LAW The relationship between temperature and volume. Remember that the law assumes that the pressure remains constant. V1 = original volume T1 = original absolute temperature V2 = new volume T2 = new absolute temperature P1 = Initial Pressure V1= Initial Volume T1= Initial Temperature P2= Final Pressure V2= Final Volume T2= Final Temperature IDEAL GAS LAW P1 = Initial Pressure V1= Initial Volume T1= Initial Temperature P2= Final Pressure V2= Final Volume T2= Final Temperature
The volume increases.
Liters is a measurement of volume. 160 Liters is the volume.
54 liters at STP (standard temperature and pressure)