C2h4
React with alcoholic KOH (dehydrohalogenation) to give 1-propene, followed by treatment with HCl (electrophilic addition).
When alc. KOH react with alkyle halide it for Alkene, KX (X Is stande for halide) and water. And this reaction also called Dehydrohalogenation...
First add aquos alcoholic KOH,then add Br2.After,add aquos alcoholic KOH again.
KOH act as a nucleufeel and react with benzil OH give electrones to benzil and berak the double bond.
They do not react, the Calcium cannot displace the Potassium as it is less reactive.
React with alcoholic KOH (dehydrohalogenation) to give 1-propene, followed by treatment with HCl (electrophilic addition).
When alc. KOH react with alkyle halide it for Alkene, KX (X Is stande for halide) and water. And this reaction also called Dehydrohalogenation...
First add aquos alcoholic KOH,then add Br2.After,add aquos alcoholic KOH again.
KOH act as a nucleufeel and react with benzil OH give electrones to benzil and berak the double bond.
in the organic reactions for dehydrogenation alcoholic KOH is used
When bromoethane is treated with alcoholic KOH ,ethene is formed which on further bromination gives 1,2dibromoethane and again treated with alcoholic KOH gives acetylene.
They do not react, the Calcium cannot displace the Potassium as it is less reactive.
Nothing, they don't react with each other.
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
because alcohol is required for dissolving both KOH and lipid
React aniline with HCl/NaNO2 (diazotisation) followed by reaction with KOH to give phenol. Nitration of phenol with fuming nitric acid gives picric acid (or trinitrophenol).
To prevent formation of soap (by substitute the water with alcohol). But indeed KOH forms an ester with fatty acids. Explain a bit the role of alcohol please. Sometimes KOH is used to conjugate and Fatty acid. When lead to saponification and when to conjugation?