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1.9 mol Se ( 78.96 grams/1mol Se ) = 150.024 grams

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Q: The mass in grams of 1.9 mol selenium?
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If you have 85.5 grams of fluorine which has a molar mass approxidmatley 19 g mol how many moles of fluorine do you have?

4.5


Calculate the number of moles present in each of the following samples.6.684e13 pg of fluorine atoms 2.435e6 mg of magnesium 3.2e-3 kg of lead(II) chloride 6.684e-5 Mg of fluorine 2.31e-9 Gg of carbon disulfide 4.91e9 ng of aluminum sulfate?

umber of Moles= Molar Mass (in g/mol) Mass (in grams) ​ First, you'll need to know the molar mass of the substance in question. Here are the calculations for each sample: 6.684e13 pg of fluorine atoms: Molar mass of fluorine (F) = 19 g/mol Mass in grams = 6.684e13 pg = 6.684e-6 g Number of moles = (6.684e-6 g) / (19 g/mol) β‰ˆ 3.52e-7 moles 2.435e6 mg of magnesium: Molar mass of magnesium (Mg) = 24.305 g/mol Mass in grams = 2.435e6 mg = 2.435 g Number of moles = (2.435 g) / (24.305 g/mol) β‰ˆ 0.1001 moles 3.2e-3 kg of lead(II) chloride: Molar mass of lead(II) chloride (PbClβ‚‚) = 207.2 g/mol Mass in grams = 3.2e-3 kg = 3200 g Number of moles = (3200 g) / (207.2 g/mol) β‰ˆ 15.45 moles 6.684e-5 Mg of fluorine: Molar mass of fluorine (F) = 19 g/mol Mass in grams = 6.684e-5 Mg = 6.684e-5 g Number of moles = (6.684e-5 g) / (19 g/mol) β‰ˆ 3.52e-6 moles 2.31e-9 Gg of carbon disulfide: Molar mass of carbon disulfide (CSβ‚‚) = 76.143 g/mol Mass in grams = 2.31e-9 Gg = 2.31e15 g Number of moles = (2.31e15 g) / (76.143 g/mol) β‰ˆ 3.03e12 moles 4.91e9 ng of aluminum sulfate: Molar mass of aluminum sulfate (Alβ‚‚(SOβ‚„)₃) = 342.15 g/mol Mass in grams = 4.91e9 ng = 4.91e-6 g Number of moles = (4.91e-6 g) / (342.15 g/mol) β‰ˆ 1.43e-8 moles


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