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The mass of a sample of nickelaverage atomic mass 58.69 amu is 11.74g how many atoms does it contain?

Updated: 11/5/2022

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∙ 7y ago

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the number of atoms is equal to the mass of the sample divided by its molar mass times one mole 11.74g / 58.69g/mol * 6.02*1023 atoms/mol = 1.2*1023 atoms approximately

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