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What is the molecular formula of 2.51 grams of C3H3O2 when dissolved in 100 grams of water?
To determine the molecular formula, we need to calculate the number of moles of C3H3O2 first. Moles = mass / molar mass. Molar mass of C3H3O2 = (312.01) + (31.01) + (2*16.00) = 72.05 g/mol. Moles = 2.51 g / 72.05 g/mol = 0.035 moles.
How many moles are in 45g of F?
The molecular mass of fluorine gas, F2 is 2(19.0) = 38.0Amount of F2 = mass of sample/molar mass = 9.5/38.0 = 0.25mol There are 0.25 moles of fluorine in a 9.5g pure sample.
How do you convert grams to molecular mass?
Suppose you have 1g of H2O and you want to convert that to moles. You multiply 1g by the inverse of molar mass to get the moles of H2O: 1g H2O *(1mol H2O/18g H2O)= 0.56 moles of H2O in 1g of H2O. You get 18g = 2(1.008)+1(16.00).
3 L of a gas weighs 2 g What is the molecular mass?
3 L / 22.414 /mole = 0.1338 moles of the gas 2 g is 0.1338 moles, or 2/0.1338 = 14.948 g/mole is the molecular weight. ( no real gas this light...methane is closest at 16 g/mole)
What is the gram molecular mass of H2SO4?
The gram molecular mass of H2SO4 is approximately 98 grams per mole. This is calculated by adding up the atomic masses of the elements in the compound: 2 hydrogen atoms (2 g/mol), 1 sulfur atom (32 g/mol), and 4 oxygen atoms (64 g/mol).
How many grams of NaCl are required to completely neutralize 100ml of 1M of H2SO4?
To completely neutralize 100 ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so you need 2 moles of NaCl for each mole of H2SO4. Therefore, you would need 2 moles of NaCl, which is equal to 117 grams (2 x molar mass of NaCl) to neutralize 100 ml of 1M H2SO4.
What mass of potassium hydroxide is required to react completely with 2.70 g of sulfuric acid to produce potassium sulfate and water?
The balanced chemical equation for the reaction is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O From the equation, it can be seen that 2 moles of KOH react with 1 mole of H2SO4. Calculate the moles of H2SO4 (2.70 g / molar mass of H2SO4) and then use the mole ratio to find the moles of KOH required. Finally, convert the moles of KOH to mass (moles of KOH x molar mass of KOH) to get the required mass of KOH.
How many grams are in 2.5 moles of sulfuric acid?
To calculate the number of grams in 2.5 moles of sulfuric acid, you first need to determine the molar mass of sulfuric acid (H2SO4). The molar mass of sulfuric acid is 98.08 g/mol. Multiplying the molar mass by the number of moles gives you the mass in grams. Therefore, 2.5 moles of sulfuric acid is equal to 245.2 grams.
What is the mass in grams of three moles of H2SO4?
H2SO4 H= 1X2 = 2 S=32X1=32 O=16X4=64 TOTAL: 98 98x3= 294 GRAMS =))
What will be the mass of 2.05 1016 molecules of H2SO4.?
To calculate the mass of 2.05 x 10^16 molecules of H2SO4, first find the molar mass of H2SO4, which is 98.08 g/mol. Then use Avogadro's number (6.022 x 10^23) to convert molecules to moles. Finally, multiply the number of moles by the molar mass to find the mass of 2.05 x 10^16 molecules of H2SO4, ~3.98 grams.
How many moles of H are in 0.75 moles of H2SO4?
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
How many moles are in 0.50 of H2SO4?
Did you mean 0.5 g? or mg? or ml?Anyway, amount of substance in moles is calculated as m/Mwhere m is mass and M is molal mass.M (H2SO4) is 1*2 + 32 + 16*4 = 98 g/mole
Millimoles to grams?
number of moles present = molar mass (g) 1 mol The molar mass is the sum of the atomic masses present in a compound. Be sure to take quantity into acount. For intance... the molar mass of H2O is 18.02 because 1.01+1.01+16=18.02
How many moles of excess sulfuric acid are left over after the reaction is complete 2 nh3 aq plus h2so4 aq nh4 2so4 aq?
To determine the moles of excess sulfuric acid left over after the reaction is complete, you need to compare the stoichiometry of the reactants. In this case, 2 moles of NH3 reacts with 1 mole of H2SO4. If you know the initial moles of NH3 and H2SO4 used in the reaction, you can calculate which one is in excess and how many moles of the excess reactant are left over.
How grams of NaOH is required to nuetralize 100 ml of 1 M H2SO4?
Since H2SO4 is a diprotic acid, it will require twice the amount of NaOH to neutralize it. Therefore, molarity of NaOH should also be 1 M. 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, to neutralize 1 mole of H2SO4, 2 moles of NaOH are required. To neutralize 1 mole of H2SO4 in 100 ml (0.1 L) of 1 M solution, you will need 0.1 moles of NaOH.
How many moles of H2SO4 will react with 18mol of Al?
The balanced chemical equation is: 3H2SO4 + 2Al → Al2(SO4)3 + 3H2. This shows that 3 moles of H2SO4 react with 2 moles of Al. Therefore, using a mole ratio calculation: (18 mol Al) x (3 mol H2SO4 / 2 mol Al) = 27 moles of H2SO4 will react with 18 moles of Al.
What mass of ironIIInitrate is needed for a chemical reaction that requires 6.00 moles of FeNO33?
To determine the mass of iron(II) nitrate needed for 6.00 moles of Fe(NO3)2, you first need to calculate the molar mass of Fe(NO3)2. Fe(NO3)2 has a molar mass of approximately 179.86 g/mol. Therefore, the mass needed would be 6.00 moles * 179.86 g/mol ≈ 1079.16 grams of Fe(NO3)2.
