(x - 1)x(x + 1) = (x2 - 1)x = x3 - x = 210.
x3 - x - 210 = (x - 6)(x2 + 6x + 35) = 0
Thus, 6 = x (or -3 +- i*sqrt(26)). The real solution, 6, can be plugged back into x - 1 (the lowest), producing 5. 5 is your answer.
the product of two consicutive multiple of three integers
lol I need to know this too.
-7
The 3 consecutive odd positive integers are 7, 9 and 11.
There is no set of three consecutive integers for 106.
9240 is the product of the three consecutive integers 20, 21, and 22.
-13, -15 and -17
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
the product of two consicutive multiple of three integers
270
Not sure what thress is. If three, then there is no answer since the sum (or product) of any three consecutive integers must be divisible by 3.
7+8+9=24 7x8x9=504
25, 26 and 27.
lol I need to know this too.
There is no set of three consecutive integers for 187.
-10, -9 and -8
-7