KOH (aq) + HCl (aq) = KCl (aq) + H20 so potassium chloride and water - KCl solution
0.377
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
KOH + HCl ---> KCl + H2O
Potassium chloride and water result from this reaction: KOH + HCl = KCl + H2O
Alkalies can neutralize both concentrated and dilute acids, but dilute acids are 'more easily' neutralized (i.e. require a smaller amount of alkali for the same amount of acid). It is a simple chemical reaction, the amount of alkali required to neutralize an acid can be calculated if you know how they react and the strengths of the acid and alkali. E.g. if you use Potassium Hydroxide (KOH) to neutralize Hydrochloric acid (HCL) the reaction is: KOH + HCL --) KCL + H2O So one molecule of KOH neutralizes one molecule of HCL If you have 1 molar KOH, then : 10 ml of dilute HCL (0.1 molar strength) will be neutralized by 1 ml of KOH 10 ml of a strong HCL (10 molar strength) will be neutralized by 100 ml of KOH Hope that helps.
0.377
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
KOH + HCl ---> KCl + H2O
Alkalies can neutralize both concentrated and dilute acids, but dilute acids are 'more easily' neutralized (i.e. require a smaller amount of alkali for the same amount of acid). It is a simple chemical reaction, the amount of alkali required to neutralize an acid can be calculated if you know how they react and the strengths of the acid and alkali. E.g. if you use Potassium Hydroxide (KOH) to neutralize Hydrochloric acid (HCL) the reaction is: KOH + HCL --) KCL + H2O So one molecule of KOH neutralizes one molecule of HCL If you have 1 molar KOH, then : 10 ml of dilute HCL (0.1 molar strength) will be neutralized by 1 ml of KOH 10 ml of a strong HCL (10 molar strength) will be neutralized by 100 ml of KOH Hope that helps.
Potassium chloride and water result from this reaction: KOH + HCl = KCl + H2O
You have : --------------------------------------… V sub 0.45M HCl = ( V sub 1.00M KOH ) ( M sub KOH / M sub HCl ) V sub 0.45 HCl = ( 25.0 ) ( 1.00 / 0.45 ) = 55.56 mL <-----------------------
When KOH reacts with HCl, these products are formed. This is a neutralization reaction. KOH is a base while HCl is an acid.
KOH + HCl -> KCl + H2O This is a neutralization reaction. You know because it produces water and a salt.
KCl
Water and a salt (a salt referring to any ionic compound). An example would be HCl neutralizing KOH. HCl+KOH-->H2O+KCl
A salt is the product of the reaction between a base and an acid; potassium chloride may be obtained from HCl and KOH: HCl + KOH = KCl + H2O
Hydrochloric acid will... HCl + KOH = KCl + H2O