10
If your starting temperature is -12 and you want to lower the temperature by 36 degrees then your final temperature is -48
If an object is dropped from rest at a height of 128 m, the distance it falls during its final second in the air is still 128 m.
Because the increments - the "step" from one degree to the next- is the same for Kelvin and Celsius. Difference is that their zero isn't at the same place. Think of two ladders starting at different heigts.
I'll assume here that by "70 temperature" you mean "70 degrees Celsius". Basically, you have to calculate the average temperature of all of the water in the mixture, which will be the final temperature once it's well stirred. The 200 grams of water at 10 degrees represent 2/3 of the total amount of water (300 grams), so thus, multiply 10 by 2/3 to determine their contribution to the final temperature. You will get 20/3. The 100 grams of water at 70 degrees represent 1/3 of the total amount of water, so multiply 70 by 1/3 to determine their contribution to the final temperature. You will get 70/3. When you add together the two temperatures you get 90/3, which is equal to 30. Therefore, the final temperature is 30 degrees Celsius.
30%
42.3 Celsius
Add a little heat.
The answer will depend on its starting temperature and its final temperature.
If your starting temperature is -12 and you want to lower the temperature by 36 degrees then your final temperature is -48
This would depend on the temperature of the water before you add the metal and what type of metal it is. if its copper it absorbs heat fast and would not change the temperature much but if you dropped lead into it then it would have to absorb more heat making the temperature lower than the copper. There are too many variables to answer the question.
40 degree
1.77
When allowed to stand for long enough, the final temperature will reach room temperature.
A nuke is dropped and everyone dies.
When allowed to stand for long enough, the final temperature will reach room temperature.
It has to do with this thermodynamic equation: q = mCP(Tf-Ti) q heat m mass Cp heat capacity Ti initial temperature Tf final temperature
The distance between the final position and the starting position is the