In a parallel circuit, the total resistance is the inverse of the total of 1 over the value of the first resistor plus 1 over the value of the second resistor. Said another way, if you take 1 over the value of R1 plus 1 over the value of R2, and then take 1 over that, you will find Rtotal. So let's do that. 1/10 + 1/2 = 1/10 + 5/10 = 6/10 1 divided by 6/10 = 10/6 = 1 2/3 ohms for the total resistance. As a quick check, in any parallel network where a group of resistive elements are all connected in parallel, the total resistance will be less than the value of the smallest one. The smallest one in this case is 2 ohms, so we are good to go by that simple check.
1.017ohms if following 1/Rtotal = 1/R1 + 2/R2 + 3/R3 formula
The total resistance is 5 ohms. Scroll down to related links and look at "Parallel Resistance Calculator".
1/R Total=1/R1+1/R2 1/R Total=1/60+1/60 1/R Total=2/60 R Total=60/2 Answer: 30 ohms
R = 1/[1/2 + 1/4 + 1/6 + 1/10]
Add up the reciprocals of the resistances, and take the reciprocal of the answer.
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R = 1/[1/2 + 1/4 + 1/6 + 1/10] Add up the reciprocals of the resistances, and take the reciprocal of the answer.
5 ohms
According to Ohm's law of resistance in parallel, 1/RT=1/R1+1/R2+1/R3... so 1/RT=1/12+1/4=1/12+3/12=4/12=1/3 and 1/(1/3)=3.The total resistance of the two devices is 3.There is a simpler special case formula for two resistances in parallel:* RTot = (R1R2) / (R1 + R2) In this case this it would give us (12 x 4) / (12 + 4), or 48 / 16 which equals 3 ohms.3 ohms
.9 watts.
A simple circuit has three resistors connected in series. The resistors are 14 ohms 12 ohms and 9 ohms. What is the total resistance of the circuit?
5 ohms.
R = 1/[1/2 + 1/4 + 1/6 + 1/10] Add up the reciprocals of the resistances, and take the reciprocal of the answer.
Well, the total circuit resistance depends on the type of connection. If the two resistances (or any number of resistances) are connected in series, IE. one resistance end is connected to one end of another resistance, the the circuit total resistance is the sum of the two resistances. say two resistances r1 and r2 are connected in series the total resistance is r1+r2 (in this case its 30 ohms). If the resistances are connected in parallel IE. both the ends of a resistance are connected to both ends of another resistance then the total resistance in this case shall be (r1*r2)/(r1+r2) ,( that is 6.67 ohms in given case).
To calculate resistance in parallel: 1/R = 1/A + 1/B + 1/C + 1/D ... where R is the final result, and A, B, C... are the individual resistances. For two resistances A and B, you can simply calculate (A x B) / (A + B).
R = 1/[1/2 + 1/4 + 1/6 + 1/10] Add up the reciprocals of the resistances, and take the reciprocal of the answer.
For an end-result of 10 ohms, you can have 1 resistance of 10 ohms, or 2 parallel resistance of 20 ohms each, or 3 resistances of 30 ohms each, etc.
The equivalent resistance of four resistors in parallel, the resistors being 2, 4, 6, and 8 ohms, is 0.96 ohms. RP = 1 / summationI=1toN (1/RI)
You can consider a short circuit to be a resistor with R=0 Ohms. It is then clear by the equation for calculation of parallel resistance that the combined resistance of a resistor in parallel to a short circuit is 0. Consider the following example with R1= 1k Ohms and R2= 0 Ohms: Rtotal = R1*R2 / (R1+R2) = R1*0 / R1 = 0 Ohms.
For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.
we have this 1/Re = (1/R1)+(1/R2) for calculating the effective resistance when resistances are connected in parallel so the answer would be Re =( 70*30) / (70+ 30) = 21 ohms
Three 8.0-W resistors are connected in parallel. What is their equivalent resistance?
The equivalent resistance is the overall effect all of the resistances in a circuit has. Put another way, it is the value a single resistor in a circuit would have to be in order to have the same effect as all of the resistors resistors combined in a given circuit.