R = 1/[1/2 + 1/4 + 1/6 + 1/10]
Add up the reciprocals of the resistances, and take the reciprocal of the answer.
For a series circuit, just add the resistances together.
No. The resistance in a series circuit is all the resistor values added together. eg. If two resistors were in a circuit, one was 10 ohms and the other was 30 ohms, the resistance in the circuit would be 30 ohms. Hope this helps!
If they're connected in series the total resistance is 2000 ohms. If they're connected in parallel the resistance is 500 ohms.
Assuming DC and resistive loads, resistance equals voltage across the load, divided by the current through it. In this case 120/10 or 12 ohms.
In a parallel circuit, the total resistance is the inverse of the total of 1 over the value of the first resistor plus 1 over the value of the second resistor. Said another way, if you take 1 over the value of R1 plus 1 over the value of R2, and then take 1 over that, you will find Rtotal. So let's do that. 1/10 + 1/2 = 1/10 + 5/10 = 6/10 1 divided by 6/10 = 10/6 = 1 2/3 ohms for the total resistance. As a quick check, in any parallel network where a group of resistive elements are all connected in parallel, the total resistance will be less than the value of the smallest one. The smallest one in this case is 2 ohms, so we are good to go by that simple check.
Ohm's law: Current is voltage divided by resistance. 50 volts divided by 5 ohms = 10 amperes.
5 ohms
5 ohms.
Three resistors in parallel: 20 ohms, 20 ohms, 10 ohms.1/ total resistance = (1/10) + (1/20) + (1/20) = (2/20) + (1/20) + (1/20) = 4/20 = 1/5 mho.Total resistance = 5 ohms
-- If the 20 ohms and the nother 10 ohms are configured in series, then the totalnet effective resistance is 30 ohms.-- If they are configured in parallel, then the total effective resistance is 62/3 ohms.
The total resistance is 5 ohms. Scroll down to related links and look at "Parallel Resistance Calculator".
For an end-result of 10 ohms, you can have 1 resistance of 10 ohms, or 2 parallel resistance of 20 ohms each, or 3 resistances of 30 ohms each, etc.
R = 1/[1/2 + 1/4 + 1/6 + 1/10] Add up the reciprocals of the resistances, and take the reciprocal of the answer.
The question appears to be describing three resistors all in parallel.The reciprocal of their net effective resistance is(1/20) + (1/20) + (1/10) = (2/20) + (1/10) = (1/10) + (1/10) = (2/10) = 1/5.The net effective resistance is [ 1 / (1/5) ] = 5 ohms.
No. The resistance in a series circuit is all the resistor values added together. eg. If two resistors were in a circuit, one was 10 ohms and the other was 30 ohms, the resistance in the circuit would be 30 ohms. Hope this helps!
If they're connected in series the total resistance is 2000 ohms. If they're connected in parallel the resistance is 500 ohms.
5 ohms
30 ohms