If they're connected in series the total resistance is 2000 ohms.
If they're connected in parallel the resistance is 500 ohms.
A circuit has an applied voltage of 100 volts and a resistance of 1000 ohms. The current flow in the circuit is 100v/1000ohms which would equal .1.
1000 ohms
"1,000 ohms" is the resistance of anything through which the current, expressed in amperes, is numerically equal to 0.001 times the potential difference between its terminals, expressed in volts.
1.5 volts
Ohm's Law: Resistance in ohms is voltage in volts divided by current in amperes.
A circuit has an applied voltage of 100 volts and a resistance of 1000 ohms. The current flow in the circuit is 100v/1000ohms which would equal .1.
Ohm's law: voltage is current times resistance 0.03 amperes times 1000 ohms = 30 volts.
ohms=amps/volts Amps= volts/ohms Volts = Amps*Ohms
ohms is the unit of resistance while volts is the unit of voltage
1000 ohms
Current, by Ohm's Law, is voltage divided by resistance, so, 18 volts divided by 2 ohms is 9 amperes.
"1,000 ohms" is the resistance of anything through which the current, expressed in amperes, is numerically equal to 0.001 times the potential difference between its terminals, expressed in volts.
Resistance(Ohms)= Voltage(volts)/Current (Ampheres) -X
total voltage = 4.5V, total resistance = 3.5 ohms, loop current = 4.5V / 3.5 ohms = 1.286Atotal voltage = 9V, total resistance = 4 ohms, loop current = 9V / 4 ohms = 2.25Atotal voltage = 13.5V, total resistance = 4.5 ohms, loop current = 13.5V / 4.5 ohms = 3Aetc.There is no solution to your problem conditions.
Taking the question at face value, the internal resistances will be treated like "real" resistors in the circuit. That means we have 3 batteries of 1.5 volts each connected in series with their 2 ohms + 2 ohms + 2 ohms of internal risistance, or 6 ohms of internal resistance. The 6 ohms of internal resistance acts in series with the 44 ohms of resistance stated as the value of the resistor. The total resistance is simply the sum of the two, or 6 ohms + 44 ohms or 50 ohms of total resistance. The batteries are connected in series, and their individual voltages are added to find total applied voltage. That means 1.5 volts + 1.5 volts + 1.5 volts or 4.5 volts will be the total applied voltage. Total current in the circuit (and through our 44 ohm resistor) will be the voltage applied divided by the resistance ( I = E / R), which, in this case, is 4.5 volts / 50 ohms which equals 0.07 amps. That's 7/100ths of an amp, or, in electronics speak, 70/1000ths of an amp, or 70 milliamps, or 70mA of current. The circuit is a series circuit, and that current, the total circuit current, will be flowing through each and every component of the circuit. That's what a series circuit means.
To calculate volts, you also need to know the resistance (ohms) in the circuit according to Ohm's Law. The formula to find volts is V = I x R, where V is voltage, I is current in amps, and R is resistance in ohms. So, to determine volts given 0.01 amps, you'd need the resistance value.
Current is inversely proportional to resistance. If you double the resistance, you halve the current. Ohm's Law: Volts = Amps * Ohms Solve for Amps: Amps = Volts / Ohms