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If they're connected in series the total resistance is 2000 ohms.

If they're connected in parallel the resistance is 500 ohms.

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A circuit has an applied voltage of 100 volts and a resistance of 1000 ohms What is the current flow in the circuit?

A circuit has an applied voltage of 100 volts and a resistance of 1000 ohms. The current flow in the circuit is 100v/1000ohms which would equal .1.


What is the voltage across a load given that the current though it equals 30mA and resistance of the load is 1000 ohms?

Ohm's law: voltage is current times resistance 0.03 amperes times 1000 ohms = 30 volts.


Formula for ohms law?

ohms=amps/volts Amps= volts/ohms Volts = Amps*Ohms


What is the difference between ohms and volts?

ohms is the unit of resistance while volts is the unit of voltage


What has greater resistance 5ohms or 1000 ohms?

1000 ohms


What is the total resistance of three resistors in parallel with values of 2 ohms 8 ohms and 14 ohms?

Current, by Ohm's Law, is voltage divided by resistance, so, 18 volts divided by 2 ohms is 9 amperes.


What is 1000 ohms?

"1,000 ohms" is the resistance of anything through which the current, expressed in amperes, is numerically equal to 0.001 times the potential difference between its terminals, expressed in volts.


What is the formula for electrical resistance?

Resistance(Ohms)= Voltage(volts)/Current (Ampheres) -X


A cell of emf 3.0 volts and internal resistance of 0.01 ohm is connected through an ammeter of 0.05-ohm internal resistance to a 5.0 rheostat by wire having a total resistance of 0.85-ohm?

total voltage = 4.5V, total resistance = 3.5 ohms, loop current = 4.5V / 3.5 ohms = 1.286Atotal voltage = 9V, total resistance = 4 ohms, loop current = 9V / 4 ohms = 2.25Atotal voltage = 13.5V, total resistance = 4.5 ohms, loop current = 13.5V / 4.5 ohms = 3Aetc.There is no solution to your problem conditions.


If three cells that each have an emf 1.5 volts and an internal resistance of 2 ohms are connected in series to a resistor of 44 ohms what is the current through the resistor?

Taking the question at face value, the internal resistances will be treated like "real" resistors in the circuit. That means we have 3 batteries of 1.5 volts each connected in series with their 2 ohms + 2 ohms + 2 ohms of internal risistance, or 6 ohms of internal resistance. The 6 ohms of internal resistance acts in series with the 44 ohms of resistance stated as the value of the resistor. The total resistance is simply the sum of the two, or 6 ohms + 44 ohms or 50 ohms of total resistance. The batteries are connected in series, and their individual voltages are added to find total applied voltage. That means 1.5 volts + 1.5 volts + 1.5 volts or 4.5 volts will be the total applied voltage. Total current in the circuit (and through our 44 ohm resistor) will be the voltage applied divided by the resistance ( I = E / R), which, in this case, is 4.5 volts / 50 ohms which equals 0.07 amps. That's 7/100ths of an amp, or, in electronics speak, 70/1000ths of an amp, or 70 milliamps, or 70mA of current. The circuit is a series circuit, and that current, the total circuit current, will be flowing through each and every component of the circuit. That's what a series circuit means.


.01 amps equal how many volts?

To calculate volts, you also need to know the resistance (ohms) in the circuit according to Ohm's Law. The formula to find volts is V = I x R, where V is voltage, I is current in amps, and R is resistance in ohms. So, to determine volts given 0.01 amps, you'd need the resistance value.


What effect are there when resistance is increased in the size of the current?

Current is inversely proportional to resistance. If you double the resistance, you halve the current. Ohm's Law: Volts = Amps * Ohms Solve for Amps: Amps = Volts / Ohms