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What is the current in a circuit with 20 volts and 5 ohms resistance?

20V / 5ohms = 4A


What is the potential difference neede to send 2a through a 5 ohms resistor?

V=I*R -- Potential (Voltage, V) = Current (Amperage, I) * Resistance (Ohms)2A*5Ohms = 10V


What is the total resistance is V is 10 volts R1 is 1000 ohms and R2 is 1000 Ohms?

If they're connected in series the total resistance is 2000 ohms. If they're connected in parallel the resistance is 500 ohms.


Is ohms bigger unit to megohms?

An ohm is a unit of electrical resistance. A kilohm is 1,000 ohms resistance, while a megohm is 1,000,000 ohms resistance.


What is ahigher resistance 10 ohm or 1 kilo ohm in other words does 1kilo ohm have more or less resistance than 10 ohm.?

Because 1 kiloohm is 1000 ohms. 1000 ohms is a higher resistance value than 10 ohms.


How much is kilo ohms?

10.2 kilo ohms is the resistance necessary for 1 volt to induce a current of 98.04 micro amperes. Ohm's law: voltage equals current times resistance.


What is the voltage across a load given that the current though it equals 30mA and resistance of the load is 1000 ohms?

Ohm's law: voltage is current times resistance 0.03 amperes times 1000 ohms = 30 volts.


Is a miliohm 1000 ohms?

No, a miliohm is 0.001 ohms. A kiloohm is 1000 ohms.


When two resister of 1000 ohms are connected in parallel their effective resistance will be?

500 ohms. RP = 1 / summation (1 / RI)


Would a 5 ohms a current of 0.5 amperis when volts is impressed acrossed it?

V=I*R, 0.5A*5ohms = 2.5Volts


A circuit has an applied voltage of 100 volts and a resistance of 1000 ohms What is the current flow in the circuit?

A circuit has an applied voltage of 100 volts and a resistance of 1000 ohms. The current flow in the circuit is 100v/1000ohms which would equal .1.


What is the amount of power loss on a transmission line that is transmitting 10 MW at 500 kV with 1000 ohms?

Line current = 10MW / 500kV = 20A Assuming the 1000 ohms is the resistance of the entire transmission line, end to end. Power loss = line current ^ 2 * line resistance = 20A ^ 2 * 1000 ohms = 400 KW