x/^2/14^2+y^2/7^2=1
bx2/14 +y2/25 =1
x2/52 + y2/93 = 1
APEXx^2/6^2 + y^2/4^2=1~PurpleLicious~
No. Both foci are always inside the ellipse, otherwise you don't have an ellipse.
No. Both foci are always inside the ellipse, otherwise you don't have an ellipse.
This ellipse is centered at the origin and has a horizontal axis of length 26 and a vertical axis of length 12 What is its equation?
A
6*4
x2/82 + y2/242 = 1
x2/82+y2/42=1
bx2/14 +y2/25 =1
x2/52 + y2/93 = 1
X^2/2^2 + y^2/4^2 = 1
apexx2/81 + y2/9 =1~PurpleLicious~
Apexx2/36 + y2/81 = 1~PurpleLicious~
Ellipse formula, centered at the origin, where the vertical axis is the major axis: x2/b2 + y2/a2 = 1, a > b Since the major axis is 8, then a = 4. Since the minor axis is 4, then b = 2. Thus, the equation of the ellipse is: x2/4 + y2/16 = 1.
x2/4^2+y2/12^2=1