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A Punnett square is used to lay out the possible genotypes of offspring based on the genotypes of the parents being bred. From this, the probabilities of certain phenotypes and genotypes can be determined.
Many possible genotypes, producing ,any possible phenotypes.
Possible genotypes would be AA and Aa. Phenotypes cannot be determined here because they are the physical, observable results of a genotype.
I think you have the question backwards, "Why isn't it possible to have more phenotypes than genotypes?" There are always more or an equal number of genotypes relative to phenotypes. The phenotype for a simple dominant/recessive interaction (for example) T for tall and t for short where TT is tall, Tt is tall and tt is short has three genotypes and two phenotypes. If T and t are co-dominant then TT would be tall, Tt would be intermediate and tt would be short. (Three phenotypes and three genotypes.)
Generally, if the parents are heterozygous and one allele is dominant over the other there are only 2 phenotypes and 3 genotypes. Parents Aa can produce AA, Aa and aa offspring. If the heterozygous individuals have an intermediate phenotype, then three genotypes and 3 phenotypes are possible. If 2 traits are being studied using heterozygous parents AaBb then the possible Genotypes are AABB, AABb, AAbb, AaBB, AaBb, Aabb, aaBb, aaBB, aabb which is nine genotypes. But there are 4 phenotypes. AABB AABb AaBB AaBb are phenotypically the same. aaBb, aaBB are phenotypically the same. Aabb, AAbb are phenotypically the same. aabb
The possible genotypes and phenotypes of the offspring can be determined using a Punnett square, a grid that shows the possible combinations of alleles that can result at fertilisation. The Punnett square below shows the expected genotypes of the offspring of parent pea plants that both have the genotype Rr.
A Punnett square is used to lay out the possible genotypes of offspring based on the genotypes of the parents being bred. From this, the probabilities of certain phenotypes and genotypes can be determined.
Many possible genotypes, producing ,any possible phenotypes.
Possible genotypes would be AA and Aa. Phenotypes cannot be determined here because they are the physical, observable results of a genotype.
Many possible genotypes, producing ,any possible phenotypes.
Mendel Diagrams. If the offspring gets a dominate gene from both parents, the offspring will exhibit traits from the dominate gene. If the offspring gets a dominate gene from one parent and a recessive gene from another, the offspring will exhibit traits from the dominate gene. If the offspring get a recessive gene from both parents, the offspring will exhibit traits from the recessive gene.
half white and half purple
I think you have the question backwards, "Why isn't it possible to have more phenotypes than genotypes?" There are always more or an equal number of genotypes relative to phenotypes. The phenotype for a simple dominant/recessive interaction (for example) T for tall and t for short where TT is tall, Tt is tall and tt is short has three genotypes and two phenotypes. If T and t are co-dominant then TT would be tall, Tt would be intermediate and tt would be short. (Three phenotypes and three genotypes.)
Generally, if the parents are heterozygous and one allele is dominant over the other there are only 2 phenotypes and 3 genotypes. Parents Aa can produce AA, Aa and aa offspring. If the heterozygous individuals have an intermediate phenotype, then three genotypes and 3 phenotypes are possible. If 2 traits are being studied using heterozygous parents AaBb then the possible Genotypes are AABB, AABb, AAbb, AaBB, AaBb, Aabb, aaBb, aaBB, aabb which is nine genotypes. But there are 4 phenotypes. AABB AABb AaBB AaBb are phenotypically the same. aaBb, aaBB are phenotypically the same. Aabb, AAbb are phenotypically the same. aabb
punnet square
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Assuming there is no co-dominance or partial dominance, the result would be that 100% of the offspring would be blue, heterozygous flowers with the phenotype Bb.