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To reduce the voltage, I need to change the voltage of 5v to 4.5v, I use a 30 ohm resistor, how many watts of resistor should I use?
To calculate the power rating of a resistor required to drop the voltage from 5V to 4.5V using a 30 ohm resistor, we can use the formula:
Power = Voltage Drop x Current
The current flowing through the resistor can be calculated using Ohm's law:
Current = Voltage Drop / Resistance
Substituting the values we get:
Current = (5V - 4.5V) / 30 ohms = 0.0167 A (rounded to four significant figures)
Now we can calculate the power required:
Power = (5V - 4.5V) x 0.0167 A = 0.00835 watts
So a resistor with a power rating of at least 0.00835 watts (or 8.35 milliwatts) should be sufficient for this application. However, it is recommended to use a resistor with a slightly higher power rating to ensure that it can handle any temporary power surges or variations in current that may occur. A 0.25 watt resistor should be suitable for this purpose.
What else can I help you with?
What size resistor in parallel to reduce from 120 volts to 100 volts?
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It does not matter. Kirchoff's Current Law states that the signed sum of the currents entering a node is zero. A consequence of that law is that the current in every part of a series circuit is the same. The only thing that resistor location affects is the potential voltage of the LED terminals with respect to the rest of the circuit. Certainly, if you are driving the LED with high voltage, such as 120VAC, you should consider the resistor location so as to reduce electrocution hazard but, the LED's performance is not affected by resistor location in the circuit.
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When measuring AC voltage across a 15-ohm resistor with a current of 12 amps, the multimeter's selector switch should indeed be set to the AC voltage position. This setting ensures that the meter can accurately measure the alternating voltage across the resistor. The voltage can be calculated using Ohm's Law (V = IR), resulting in a voltage of 180 volts (V = 12 A * 15 Ω). Make sure the multimeter is rated for the expected voltage level to ensure safety and accuracy.
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