MAT=RAT - [(RAT - DT) * ((100 - %HA)/100)]
MAT = mixed air temperature
ODT = outdoor design temp.
RAT = return air temp. (68)
DT = HRV air delivery temp.
%HA = percentage of house air
from the equation of state pressure = density * gas constant * temperature
No. The temperature of the unit would be at the ambient temperature of the room.
Air will flow out of a building when the outside temperature is warmer.
themperature of out door air plus temperature of return air [furanace]
The speed of sound in air changes clearly with temperature, a little bit with humidity − but not with air pressure (atmospheric pressure).Statement: The static air pressure p_ and the density ρ of air (air density) are proportional at the same temperature, because the ratio p_ / ρ is always constant, on a high mountain or even on sea level altitude.Notice: The ratio p_ / ρ (static air pressure to air density) is really always constant.
from the equation of state pressure = density * gas constant * temperature
The answer is 7
There is water mixed in with all the atmopshere around us. Nomatter what temperature the air is, there's always going to be some water mixed in it. Take a moment to think what it would be like if the atmosphere was 100 degree celcius: all the water would boil off the earth and become a gas mixed in with the air. The same is true at lower temperatures, water evaporates and becomes mixed in with the air. The higher the temperature, the more water that can be held by the air, the lower the temperature, the less water that can be held. When you open your freezer door, some moisture from the room temperature air gets in with the cold air. As the temperature drops in the freezer, the water from the air can't be held by the air anymore, so it accumulates with other water molecules or the nearest surface. If you leave the cup in long enough, the water will freeze to the cup until you bring it out. This is also how some Dehumidifying machines work, too! Just a fun fact. Happy cup freezing! -Jp
The question is wrong. With rising temperature the speed of sound is also rising. Air temperature affects the speed of sound. The formula to find the speed of sound in air is as follows: c = 331 m/s + 0.6 m/s * T (°C) c is the speed of sound and T is the temperature of the air. One thing to keep in mind is that this formula finds the average speed of sound for any given temperature. The pitch of woodwind instruments goes up, when the temperature goes up.
Ice temperature is 32 degrees, F. or less.
Sorry, the atmospheric pressure has really nothing to do with the speed of sound at 0c, but he temperature is very important Scroll down to related links and read the short article "Speed of sound - temperature matters, not air pressure". The air pressure and the air density are proportional to each other at the same temperature.
The gases air consists of are roughly described by the formula pV=nRT, where p is pressure, V is volume, n is the number of molecules/atoms, R is the gas constant and T is temperature. As the temperature rises, so will the pressure.
Because the temperature is often a few degrees colder right at the surface. This is because cold air sinks, and if it is not mixed (as under calm conditions) the temperature will be colder at the surface than it is 2 meters above ground, where temperature is officially measured.
Air temperature greatly affects water temperature. When the sun is strong, it increases the temperature of the air and water. On the other hand, when the sun is less intense, the temperature of the air and water decreases.
Higher temperature air is less dense.Less-Dense air has a higher temperature
Yes, but the speed of sound is slower then. The formula to find the speed of sound in air is as follows: c = 331 m/s + 0.6 m/s * T (°C) c is the speed of sound and T is the temperature of the air. One thing to keep in mind is that this formula finds the average speed of sound for any given temperature. The pitch of woodwind instruments and pipe organs goes down, when the temperature goes down.
Speed of sound c = λ × f Wavelength λ Frequency f Formula: Temperature of air ϑ ≈ (c − 331.3) / 0.6 in °C. Temperature of air ϑ If c = λ × f = 343.3 m/s then the temperature is ϑ ≈ (343.3 − 331.3) / 0.6 = 20°C.