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You would have to lift a given mass (m) a certain distance(h) and work out the amount of energy(work) this has taken using W=mgh, where g is acceleration due to gravity. Then you would have to use a torque metre to wind the jack , and using the number of turns needed to lift the weight, calculate the amount of work done, using E= torque x angle travelled(in radians). In an ideal frictionless jack the two figures would be the same. The difference between the two is the amount of energy lost to friction.The mechanical advantage you mention is related to the pitch of the screw or thread.That is,a fine thread pitch can lift more weight using only human force, but with a greater number of turns.I should also mention that in a diamond shaped,lever type jack, the mechanical advantage increases, and the torque required decreases, the higher the jack is extended. It becomes a little more complicated, involving vectors, angles, and maybe even calculus. Perhaps another poster could help here.

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Q: To find the mechanical advantage load lost in friction of screw jack?
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