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Use the ideal gas law, PV = nRT

when using L for Volume, pressure used must be in Kpa.

Therefore P must be converted to Kpa

and T must be converted to Kelvin

since nR are the constants, nR for both will be the same

therefore

lets say P1 and V1 and T1 is the p and v and t before heating AND P2 V2 is the p and v after heating.

P1V1/T1 = P2V2/T (find T)

T = P2V2 / (P1V1/T1)

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Q: To what temperature must 15 L of oxygen gas at 0 C be heated at 1 ATM pressure in order to occupy a volume of 23 L assuming that the pressure increases by 50 mm Hg?
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