The brightness of a light bulb is related to its power. In all electrical circuits, power is equal to Voltage*Current. Since the two bulbs are connected in series, they must have equal current. The voltage across any given element in a series circuit is proportional to its resistance, so whichever bulb has the higher resistance has a higher voltage and thus higher power and is brighter.
In a parallel circuit, if both light bulbs have the same amount of resistance (such as 12 Ohms each) they will also have equal brightnesses. HOWEVER if there are resistors or other similar components in the circuit in some places, then one light bulb will be brighter than the other or even not shine at all.
Connecting light bulb is equivalent to connecting a resistance. If you have connected light bulb, there will be some voltage drop across it and your TV may not get sufficient voltage. However if resistance is not big enough, than it wont have any effect.
If they have the same resistance they will. Kirchhoff's' Law.
No. In a parallel circuit, the resistance gets cut in half, so logically the bulbs would do the opposite and get brighter.
It depends on the circuit. If it is a constant-current circuit, any light bulbs connected in parallel with it will become brighter. If it is a constant-voltage circuit like a typical household circuit, nothing will happen. Any connected in series with it will go out.
Since the bulbs are in series, each one will have 40 volts across it instead of the 120 volts it was designed for. The bulbs will glow very dimly or not at all.
Two bulbs connected in parallel are brighter than two connected in series. The resistance of the circuit is lower, electrons can flow more easily.
No, the highest wattage bulb will have the lowest resistance.
If a fourth bulb were added in a similar way to the three existing bulbs, the resistance in the circuit would go up if the bulbs were series connected, and it would go down if the bulbs were parallel connected.
Brighter in parallel. In series the voltage is divided between the two bulbs, thus the current will only be half so that the power of each bulb will only be one quarter (of 5 watts) in the series set-up.
In parallel, each bulb will have full voltage applied across them. However, in series, the voltage across each bulb won't be the same as supply voltage. Thereby, bulbs connected in parallel will glow brighter.
The 2 bulb series circuit , a 3 bulb series circuit will increase resistance and therefore reduce the voltage across the bulb. The current in all points of the circuit will remain the same according to Kirchhoff.
This question is the wrong way round. Assuming you the light bulbs are identical, they are brighter when connected to the power source in parallel than in series. This is because each bulb uses the entire potential difference of the power source, whereas in series, the bulbs act as potential dividers, reducing the voltage across the others and therefore the current passing through all of them.
It depends on the voltage rating of each lamp, and the value of the supply voltage. It's important to understand that a lamp will only operate at its rated power (therefore at its full brightness) when subject to its rated voltage.So, let's assume each lamp is rated at, say, 24 V.If connected in parallel across a 24-V supply, then they will both operate of full brightness.If connected in series across the same 24-V supply, then each lamp will be subject to half its rated voltage, and will be very dim.On the other hand, if connected in series across a 48-V supply, then they will each be subject to 24 V, and will both operate at full brightness.
In parallel.
The circuit voltage or the resistance of the individual bulb is needed to answer this question. Divide the total power (400 W) by the supply voltage.
Bulbs that are connected in parallel would be the same brightness as a bulb on its own. If the bulbs were in series with other bulbs, then they would be dimmer. The voltage would drop across a series.
2nd one...