If a fourth bulb were added in a similar way to the three existing bulbs, the resistance in the circuit would go up if the bulbs were series connected, and it would go down if the bulbs were parallel connected.
The total resistance in a series circuit is determined by adding (summing) the individual resistances of each component in the circuit.
This is a very technical electrical question that may be difficult to understand without further study. But adding appliances to an outlet is the same as adding resistance in parallel. Adding resistance in parallel, the resistance of the circuit goes down. That is why you get more current flow. By contrast, adding resistance in series increases the resistance of the circuit and therefore reduces current, all else being equal.
If the circuit consists of resistors only, you simply add the values of all the resistors, in ohms.
Yes
Hot resistance is your total resistance you can have with out exceeding your wattage limit
Total resistance decreases.
reduces it from 1/2 to 1/3rd
The total resistance of the original light bulbs are: 1/(1/R1 + 1/R2) The total resistance after the addition of the third light bulb is: 1/(1/R1 + 1/R2 + 1/R3) Therefore, if the resistance of the third light bulb is not infinity, 1/R3 will be greater than 0 and and adding a greater-than-0 number to the denominator of a fraction will lower the value of the fraction. Therefore, the total resistance will lower. Intuitively, you can think that adding a third bulb is opening up another possible path for electrons to flow through, therefore decreasing total impediment to electron flow.
Adding any additional element in parallel will reduce the combined resistance. Do some sample calculations to get a "feel" for this: Total resistance (R) is calculated as 1/R = 1/R1 + 1/R2 + 1/R3... In other words, take the reciprocal of the individual resistances, add them, and then take the reciprocal of the result.
The total resistance in a series circuit is determined by adding (summing) the individual resistances of each component in the circuit.
by adding the the resistances in series the total resistance of the circuit increses and thus the crunt flowing in the circuit decrese. Ans 2 . the current in series circuit of constant resistance will always be the same . It will not effect the current .
Total resistance decreases:1/R(total) = 1/R1 + 1/R2 + 1/R3Assuming each lightbulb has the same resistance: R1 = R2 = R31/R(total) = 1/R = 1/R + 1/R = 3/RR(total) = R/3Before the bulb was added:1/R(total) = 1/R + 1/R = 2/RR(total) = R/2R/3 < R/2
This is a very technical electrical question that may be difficult to understand without further study. But adding appliances to an outlet is the same as adding resistance in parallel. Adding resistance in parallel, the resistance of the circuit goes down. That is why you get more current flow. By contrast, adding resistance in series increases the resistance of the circuit and therefore reduces current, all else being equal.
Many circuits have safety devices such as fuse. A fuse contains a substance that melts if it gets hot. if a short circuit happens, the heat causes the fuse to melt. The circuit is broken. because the current stops ,no damage is done.
If the circuit consists of resistors only, you simply add the values of all the resistors, in ohms.
This is a direct consequence of Ohms Law. Since each new resistor connected in parallel will allow more current to flow, the resistance of the circuit must be lower. R = E/I. Since I (current) has increased, and the voltage E is still the same, it follows that R (resistance) must be smaller. That's the way Ohms Law works.
An ammeter has a finite resistance which is inserted in series with the rest of the circuit, increasing the total resistance and decreasing the current. A good ammeter has a very low resistance, so it shouldn't affect the circuit noticeably.