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If a fourth bulb were added in a similar way to the three existing bulbs, the resistance in the circuit would go up if the bulbs were series connected, and it would go down if the bulbs were parallel connected.

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Q: What is the effect on total resistance of adding this third bulb?
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What is the answer for threr are two light bulb in a circuit wired in parallel a third light bulb is added again in parallel What is the effect on total resistancr of adding this third bulb?

Total resistance decreases.


There are two light bulbs in a circuit wired in parallel a third light bulb is added agin in parallel what is the effect on total resistance of adding this third bulb?

reduces it from 1/2 to 1/3rd


There are 2 light bulbs in a circuit wired in parallel a third light bulb is added in parallel what is the effect on total resistance of addin the third bulb?

The total resistance of the original light bulbs are: 1/(1/R1 + 1/R2) The total resistance after the addition of the third light bulb is: 1/(1/R1 + 1/R2 + 1/R3) Therefore, if the resistance of the third light bulb is not infinity, 1/R3 will be greater than 0 and and adding a greater-than-0 number to the denominator of a fraction will lower the value of the fraction. Therefore, the total resistance will lower. Intuitively, you can think that adding a third bulb is opening up another possible path for electrons to flow through, therefore decreasing total impediment to electron flow.


There are two light bulbs in a circuit wired in parallel a third bulb is added what is the effect on tolal resistance of adding the third bulb?

Adding any additional element in parallel will reduce the combined resistance. Do some sample calculations to get a "feel" for this: Total resistance (R) is calculated as 1/R = 1/R1 + 1/R2 + 1/R3... In other words, take the reciprocal of the individual resistances, add them, and then take the reciprocal of the result.


How is the total resistance in a series circuit is determined?

The total resistance in a series circuit is determined by adding (summing) the individual resistances of each component in the circuit.


What is the affect of a series circuit on current?

by adding the the resistances in series the total resistance of the circuit increses and thus the crunt flowing in the circuit decrese. Ans 2 . the current in series circuit of constant resistance will always be the same . It will not effect the current .


There are two light bulbs in a circuit wired in parallel a third light bulb is added again in parallel what is the effect on total resistance of adding the third bulb?

Total resistance decreases:1/R(total) = 1/R1 + 1/R2 + 1/R3Assuming each lightbulb has the same resistance: R1 = R2 = R31/R(total) = 1/R = 1/R + 1/R = 3/RR(total) = R/3Before the bulb was added:1/R(total) = 1/R + 1/R = 2/RR(total) = R/2R/3 < R/2


What happens to the overall resistance of a circuit when too many appliances are connected across a 120 V outlet?

This is a very technical electrical question that may be difficult to understand without further study. But adding appliances to an outlet is the same as adding resistance in parallel. Adding resistance in parallel, the resistance of the circuit goes down. That is why you get more current flow. By contrast, adding resistance in series increases the resistance of the circuit and therefore reduces current, all else being equal.


What effect does adding devices have on the resistance of a series circuit?

Many circuits have safety devices such as fuse. A fuse contains a substance that melts if it gets hot. if a short circuit happens, the heat causes the fuse to melt. The circuit is broken. because the current stops ,no damage is done.


How is total resistance calculated in a series circuit?

If the circuit consists of resistors only, you simply add the values of all the resistors, in ohms.


What does adding more resistors to a paralles circuit decrease the equivalent resistance of the circuit?

This is a direct consequence of Ohms Law. Since each new resistor connected in parallel will allow more current to flow, the resistance of the circuit must be lower. R = E/I. Since I (current) has increased, and the voltage E is still the same, it follows that R (resistance) must be smaller. That's the way Ohms Law works.


1 What is the effect caused by the ammeter resistance when an ammeter is inserted into a circuit to measure the current?

An ammeter has a finite resistance which is inserted in series with the rest of the circuit, increasing the total resistance and decreasing the current. A good ammeter has a very low resistance, so it shouldn't affect the circuit noticeably.