This never stipulates that they are playing each other, so the answer seems simple... they both played 5 games against 5 different people and ended up winning the same number of games. Not even a large coincidence.
their playing other people not each other...
they are not playing each other
none of them are playing
They didn't play each other.
They’re not playing against each other
none of them are playing
They weren't playing eachother.
They play checkers with different people other than each other
They didn't play against each other.
The statement "Two men play 7 games of checkers, each man gets the same number, and there is no tie" suggests that the total number of games played is an odd number, specifically 7. Since there are no ties mentioned, it implies that there must be a clear winner in each game. In checkers, each game can only have one winner, as the objective is to capture all of the opponent's pieces or block them in a way that they cannot make a move. If each man plays 7 games and there are no ties, then each man must win a total of 3 games (since 3 + 3 = 6) with 1 game remaining. In the last game, one of the men will win, making the total number of wins for each man equal. So, the scenario described ensures that each man wins the same number of games (3 each), and there is no tie.
They aren't playing against each other.
They are playing with separate people.
There is no reason to assume they are playing each other throughout.
The two women are not playing each other, but rather other opponents.
Twelve (12) playing pieces are given to each of two players in the game of checkers played in the United States of America. But the number is greater in France. In a game there, each player is given 20 pieces.
They are not playing against each other.
The two men are not playing each other. They're not yet done, they just finished the fourth game.