B. would have different phenotypes, 1.b 2.c 3.d 4.b 5.c 6.c 7.c 8.c and this
In genetic notation, capital letters are used for dominant alleles. Therefore both TT and Tt would have the same phenotype - the trait produced by T (because this is dominant over t).
would have different phenotypes
tall; Tt or TT
both must be tt
If the two parent pea plants have Tt traits, they will create TT, Tt, Tt, tt. 1 TT - homozygous dominant, 2 Tt - heterozygous, and 1 tt - homozygous recessive.
For example, if the tall plant stand for T, the genotypes are: TT tt
If tall (T) is dominant and small (t) is recessive, and both are homozygous, they would all be tall. (100% tall, heterozygous.) If the tall is heterozygous, it would be 50% tall heterozygous and 50% short heterozygous.
tall; Tt or TT
P1: tt F2: tt
TT or Tt
both must be tt
both must be tt
Using a punnett square you get the results of TT, TT, Tt, Tt. Key= T-tall t-short It's going to be tall but can have different genotypes
Either TT or Tt, where T stands for dominant gene for tallness and t for recessive gene.
3 : 1 ( since the given situation of segregating genotypes TT Tt Tt tt comes under monohybrid genetic combination, it will show 3 tall plants and 1 dwarf plant because gene T is dominant over t.
If the two parent pea plants have Tt traits, they will create TT, Tt, Tt, tt. 1 TT - homozygous dominant, 2 Tt - heterozygous, and 1 tt - homozygous recessive.
I think you have the question backwards, "Why isn't it possible to have more phenotypes than genotypes?" There are always more or an equal number of genotypes relative to phenotypes. The phenotype for a simple dominant/recessive interaction (for example) T for tall and t for short where TT is tall, Tt is tall and tt is short has three genotypes and two phenotypes. If T and t are co-dominant then TT would be tall, Tt would be intermediate and tt would be short. (Three phenotypes and three genotypes.)
For example, if the tall plant stand for T, the genotypes are: TT tt
both must be tt or both must be Tt