It sounds like you're talking about Mendelian Genetics. ;-)
If by hybrid pea you mean heterozygous, then you're look at two Aa genotypes, ya? So if you just set up your Punnett square...
(Hopefully the formatting will hold)
A a
---------------------
A| AA Aa
a| Aa AA
So you get 2 phenotypes! 75% of the offspring will be tall plants (because AA, Aa, and Aa will all produce tall plants), and 25% of the offspring will be short plants (only AA can produce short plants).
But if you think your plants are homozygous (AA), then you'll only get 1 phenotype, they'll all be just like the parent plants (tall)!
Tt Tt
Their offspring will be heterozygous recessive.
224
visual inspection of phenotypic traits.
tall.
This is a form of incomplete dominance.
Punnet square
you have a 1:3 chance of the offspring having white eyes
Assuming there is no co-dominance or partial dominance, the result would be that 100% of the offspring would be blue, heterozygous flowers with the phenotype Bb.
Yy
You can find more information on inheritance on scienceprimer.com/x-linked-inheritance
Their offspring will be heterozygous recessive.
You can find more information on inheritance on scienceprimer.com/x-linked-inheritance
If the flowers are something like PP (purple) and pp (pink), then the flowers will be Pp if you do the traditional square used in most high school classes.
The offspring will get the traits of Homozygous BB .
The offspring will get the qualities , traits of homozygous BB.
The offspring are usually sterile.
that the parents were true-breeding for contrasting traits. NOT TRUE. If so, all the offspring would be identical genotypes. Think of a classic cross that gives you a 3:1 ratio and write it out. It would suggest that the parents were both heterozygous for a single trait.