The offspring will get the traits of Homozygous BB .
the offspring will get the traits of father BB.
Assuming there is no co-dominance or partial dominance, the result would be that 100% of the offspring would be blue, heterozygous flowers with the phenotype Bb.
A heterozygote means different-joineda homozygote means same-joinedso lets look at this cross. (parent genotype are Bold and italics)---B----bB | BB | Bb |--------------------B | BB | Bb |We see that 2 "joined" zygotes are BB and 2 are BbSO by definition 2 combinations produce a heterozygote "Bb"and 2 produce a homozygote "BB"
Bb The phenotype is what the individual looks like. The genotype is the genetic material at the site that can be passed on even if it isn't expressed. For example: Animal with black hair bb (can only pass the black characteristic on to it's offspring because it is homozygous recessive). It is phenotypically black. An animal with red hair can be Bb or BB. Bb is heterozygous and the animal is phenotypically red. BB is homozygous dominant for red and the animal is phenotypically red. More information than requested but an explanation none the less.
Heterozygous
dominant alleles will always overrule recessive alleles. So if you have any dominant allele in the phnotype or geneotype, the dominant trait will be expressed. For example, since black fur is dominant to brown fur on mice, if two black mice mate, at least part of their offspring will have black fur. If they are heterozygous for black, though, that's when a brown mouse offspring may be possible, but there would always be more black offspring than brown offspring. parents offspring (4) Bb x Bb --> BB, Bb, Bb, bb BB x Bb --> BB, BB, Bb, Bb BB x BB --> BB, BB, BB, BB BB x bb --> Bb, Bb, Bb, Bb Bb x bb --> Bb, Bb, bb, bb anything with a capital B would be black while "bb" is the only brown.
The offspring will get the qualities , traits of homozygous BB.
Assuming there is no co-dominance or partial dominance, the result would be that 100% of the offspring would be blue, heterozygous flowers with the phenotype Bb.
Both parents were heterozygous (Bb). The offspring would statistically be: BB, Bb, Bb, and bb. All but the bb offspring would be black and the bb would be brown.
It's heterozygous. Heterozygous is when there is a big letter and a little letter, like Bb. Homozygous is when both letters are the same size, like BB or bb.
No, homozygous recessive indivuals MUST have two of the reccessive gene (bb), the possible combinations are bb,bb,bb,bb thus only a recessive trait is possible
75% or 3/4. The two F1 (offspring) mice have a genotype Bb, and express the dominant (brown) trait. When they mate, 1/4 will be BB (homozygous dominant - brown), 2/4 will be Bb (heterozygous - brown), and 1/4 will be bb (homozygous recessive - white).
A heterozygote means different-joineda homozygote means same-joinedso lets look at this cross. (parent genotype are Bold and italics)---B----bB | BB | Bb |--------------------B | BB | Bb |We see that 2 "joined" zygotes are BB and 2 are BbSO by definition 2 combinations produce a heterozygote "Bb"and 2 produce a homozygote "BB"
Phenotype: Black Bear x Brown Bear Genotype: BB x bb Possible gametes: B B b b Possible B B crosses: b Bb Bb b Bb Bb Phenotype of offspring: Only Black bears
depends if the black fur gene is dominant.. if it is... then yu would cross BB with bb making all heterozygous genotypes(Bb) therefore, having all possible offspring with black fur so theres a 100% probability of offspring with black fur(:
"BB" and "bb" are Homozygous"Br" are hetrozygous
Yes .. Blue eye color is a recessive allele. So hence when two homozygous recesive alleles are paired, then the succesive generation will also have homozygous recessive alleles.. Like in this case : Father - bb Mother - bb Children - bb,bb,bb,bb So its 100% homozygous recessive.. :)
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.