As we know V=IR, by changing the voltages in the two different circuits, we can maintain the same current even we have different resistance.
in voltmeter we have internal Resistance and connected in series , to current don't transfer in voltmeter , and we have internal resistance in ammeter and connected in parallel , to most current transfer through the ammeter.
how do you use ohms law express conductance in terms of current and voltage?
The ratio of voltage to current is called resistance. In hydraulic terms, you can equate voltage to the difference in pressure between two points, current with the resulting flow of fluid between those points , and resistance as the opposition to that flow.
when we look at the curve ,, we can see that before the peak point curve has greater slope as compared to the slope after the peak point .. the reason is PL is given as I^2RL ,,, current is a squared term here . before peak point current is greater so overall change in power is much greater but after peak point RL is greater and current is less now the load resistance is not a squared term... so slope will be less. therefore the curve is not symetrical
Meggar is a hand driven tool for measuring insulation resistance and earth resistance.
Ohms' law says if voltage stays constant resistance controls the current flow. Resistance goes up, current goes down. E/I*R.
Current is the flow of electrons in a system usually taught from positive to ground or zero potential. It is defined by the formula current = voltage/resistance Everything has resistance - even wire.
in voltmeter we have internal Resistance and connected in series , to current don't transfer in voltmeter , and we have internal resistance in ammeter and connected in parallel , to most current transfer through the ammeter.
Let me explain the concept of a voltage drop and let us forget the lamp for now. Voltage drop is the result of an electrical current flowing through an resistance. Ohms Law state that: V = I x R R = Resistance in ohms I = Electrical current in ampere V = Potential difference in voltage or in our example we can call it the voltage drop Regardless of where a resistance is found in an electric circuit. The product of its resistance and the current flowing through it will results in a voltage drop across the resistance. If I have a 22ohm resistor in a circuit and on any given instant a 2 ampere current is flowing through it. The voltage across the resistor is 44V. Thus 44V is the voltage drop regardless of what the supply voltage is. But not only resistors has resistance, in fact all electrical components have some form of resistance even the conductors, cables, connectors and switches. Other common examples of resistances are: *Internal resistance of batteries *Light bulbs *Electric motors *Electromagnets They all have resistance, any conductor or semiconductor what is practically used will have a resistance to it and can therefore have a voltage drop if electrical current flow through it. The methods used in this example should never be attempted in AC circuits because the effects of magnetic fields and electric field may produce different results. Pure resistance only apply to DC circuits. Sufficient inductive and capacitive reactances especially in equilibrium may produce dangerous voltages in AC circuits.
how do you use ohms law express conductance in terms of current and voltage?
The ratio of voltage to current is called resistance. In hydraulic terms, you can equate voltage to the difference in pressure between two points, current with the resulting flow of fluid between those points , and resistance as the opposition to that flow.
Advantages in electric circuits : Advantages of using the rheostat in electric circuits is optional as you could just use the dial on the power-supply to vary the voltage (p.d.), and therefore the current. The advantage of using the rheostat is that you can control it to give you nice even numbers for the voltage.
Induction-type instrument measure power in alternating-current circuits and are the type commonly seen on the outside of houses.
i want the details regarding the branch circuits
You have not provide enough information. You don't explain what 0.05 references. You need to know the secondary voltage and resistance to calculate current.
explain the flow of current in ignition system
I'm not quite sure what context you mean. V=IR to explain this in words you would simply say the voltage (V) of a circuit would be equal to the current (I) multiplied by the resistance(R). a practical example could be, if the resistance in a circuit was 2 and the current was 12 what is the voltage? well using Ohms law we would simply do (2 * 12) the voltage would be 24. [note, i do not know if that would work in real life it's just a example using numbers] you can aslo rearrange V=IR to work out how to calculate current and resistance V=IR I = V/R. Current equals votlage divided by resistance R=V/I. Resistance equals voltage divided by current hope this helps