the ampere i=0is theonlyedge where the e0b and e0c can come together and share the load and that way the two vector diagrams will connected and the load will be less resistive and more on the ek0 and c73 resistive load. the 38f93 relay will be the one to break the load 2u3 and e0b and e0c into diffrent components that will be drawn in the diagram.
When working on a current transformer the secondary windings must be shorted. <<>> Properly loaded
Output voltage (...of a transformer, for example...) will decrease as it is loaded because of the transformer's internal resistance. As output current increases/load resistance decreases, a larger voltage will be dropped across the internal transformer resistance. This same phenomenon is present in AC and DC systems (such as batteries).
It's easily done if you can measure the power drawn at the normal working voltage but with no load on the transformer (open-circuit secondary). All the power is core loss with the exception of a (very) small amount of resistive loss in the primary winding.
actully when load of alternator fluctuates it changes the torque at primovers which changes amps so terminal voltage of alternator changes.
Back to back test give data for finding the regulation , efficiency and heating under load condition. Back to back test is performed in the presence of two identical transformer. In this test one transformer remains open and other remains loaded. Hence sumpner's back to back test is generalised form of o/c test and s/c test which is performed within one test only. Hence from this test we find core loss and full load copper loss simultaneously at a time.
i understand that YNaOd1 represent an auto transformer with HV winding as wye connected and loaded tertiary. Please correct me if i am wrong.
when your current transformer is over loaded make sure it turns back into a car and drives away
When working on a current transformer the secondary windings must be shorted. <<>> Properly loaded
no becouse transformer function depends on no of coil in primary and secondry coil
The lower the impedance, the lower the voltage drop across the transformer as it is loaded. This means regulation is better, since voltage variance is smaller.
The lower the impedance, the lower the voltage drop across the transformer as it is loaded. This means regulation is better, since voltage variance is smaller.
zero
The primary current on a loaded transformer depends on the secondary current, which is determined by the load. So, if you know the secondary load current, then you can use the turns ratio of the transformer to determine the primary current:Ip/Is = Ns/Np
Output voltage (...of a transformer, for example...) will decrease as it is loaded because of the transformer's internal resistance. As output current increases/load resistance decreases, a larger voltage will be dropped across the internal transformer resistance. This same phenomenon is present in AC and DC systems (such as batteries).
100%. It not practically possible to achieve 100% though. There are iron and copper losses even if it is not loaded.
this is a loaded question , depending on which system you have depends on the wiring its different with each system.
The terms, 'primary' and 'secondary', describe how a transformer is connected and his nothing to do with which is the lower- and higher-voltage winding.The primary winding is the winding connected to the supply, while the secondary winding is the winding connected to the load. So, for astep-up transformer, the secondary winding is the higher voltage winding, whereas for a step-down transformer, the secondary winding is the lower voltage winding.For a loaded transformer, i.e. a transformer whose secondary is supplying a load, the higher-voltage winding carries the smaller current, while the lower-voltage winding carries the higher current.