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What is the molarity of an naoh solution if 4.37ml is titrated by 11.1 ml of 0.0904 m hno3?
0.289 Moles is the molarity of an NaOH solution if 4.37 ml is titrated by 11.1 ml of 0.0904m hno3.
What is the molarity of 5.00 g of NaOH in 750.0 mL of solution?
67
What is the molarity of 7.0 mL of 6.0 M NaOH?
0.105 moles
What is the molarity of a solution with 2 moles of NaOH in 1620ml of water?
1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============
What is the molarity of a solution of 95 grams of NaOH to 450 ml of water?
95g NaOH * 1 mol NaOH/ = 2.375 mol NaOH 40g NaOH Molarity (M) = mol / L M = (2.375) / (0.450) M = 5.28
What is the molarity of an naoh solution if 4.37ml is titrated by 11.1 ml of 0.0904 m hno3?
0.289 Moles is the molarity of an NaOH solution if 4.37 ml is titrated by 11.1 ml of 0.0904m hno3.
What is the molarity of a solution that contains 10.0g of NaOH in 400.0 ml of NaOH of solution?
The answer is 0,625 moles.
What is the molarity of 7.0 mL of 6.0 M NaOH?
0.105 moles
What is the molarity of 5.00 g of NaOH in 750.0 mL of solution?
67
What is the molarity of a solution with 2 moles of NaOH in 1620ml of water?
1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============
What is the molarity of a solution of 95 grams of NaOH to 450 ml of water?
95g NaOH * 1 mol NaOH/ = 2.375 mol NaOH 40g NaOH Molarity (M) = mol / L M = (2.375) / (0.450) M = 5.28
What is the molarity of 32.0 of NaOH in 450 of NaOH solution?
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
How many moles of NaOH are present in 24.5 mL of 0.130 M NaOH?
Molarity = moles of solute/Liters of solution ( 24.5 mL = 0.0245 L)Rearranged,moles of solute = Liters of solution * MolarityMoles NaOH = (0.0245 L)(0.130 M NaOH)= 3.19 X 10 -3 moles NaOH==================
A 25.0 ml sample of hcl was titrated to the endpoint with 15.0 ml of 2.0 normality naoh what was the normality of th hcl what was its molarity?
The HCL concentration is 1.2M or 1.2N
27.0 ml of 0.45 m naoh is neutralized by 20 ml of an hcl solution the molarity of the hcl solution is?
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
What is the molarity of 5.60 mol of sodium carbonate in 1500-mL of solution?
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
How many moles of hydroxide are in 18.00 mL of 0.1123M NaOH?
Molarity = moles of solute/Liters of solution (18.00 ml = 0.018 Liters)0.1123 M NaOH = X moles solute/0.018 L= 2.021 X 10 -3 moles NaOH============================as all is one to one,2.021 X 10 -3 moles OH -==================
