500 newtons on earth is 51kg or 112.4 pounds.
500 newtons. (Roughly 112.3 pounds.)
The "500 - n" you mention is either the woman's name or her weight. If it's her weight, then that is in fact the size of the mutual gravitational forces between her and the Earth. It's her weight on Earth, and it's Earth's weight on her.
The magnitude of the force is 500 N. The direction is toward the center of the earth, i.e. downward.
The force acting on the woman is equal to 500 N as stated in the question!. Remember: Force (N) = Mass (kg) x Acceleration (ms-2). As such to create that force an acceleration must act on a mass. The gravitational acceleration at Earth's surface is equal to approximately 9.82 ms-2. As such a woman who weighs 500 N would have a mass of approx 50.9 kg.
500 Newtons is equivalent to approximately 112.40 pounds.
The force of gravity acting on the woman would be equal to her weight, which is 500 N. This is because the force of gravity provides the necessary force to keep her "weight" balanced on the Earth's surface.
Newton is a unit of force, kilogram is a unit of weight, so the two are actually quite different.On Earth, the gravity is about 9.8 meters per second square, which is the same as 9.8 Newton per meter, so the 500 kg. would weigh almost 5000 Newton. Weight is a force, so of course you measure it in units of force.
Newton is the amount of force required to accelerate an object of mass m to meter , In this case if we try to accelerate it to one meter , you require 500 newtons to lift the box perpendicularly. Also lifting of weight depends on the angle of applied force.
Jupiter's surface gravity is about 2.5 times that on Earth. So a mass of 500 grams would have a weight of about 1250 grams weight.
equation: weight= mass*gravity weight = 50kg * 9.8 m/s or 10 m/s (samething) =500 newtons or 490 newtons ~hope that helped!
The torque produced by the force is 15,000 Nm (Newton-meters). This is calculated by multiplying the force (500 N) by the distance from the pivot point (30 m). Torque is a measure of rotational force.
50 Newton.